Answer:
Carbohydrates: Carbohydrates are the most abundant organic molecules in nature. stored in the body in the liver and muscles in the form of glycogen.
Proteins and Amino Acids: Proteins are the most abundant organic molecules of the living system. There are twenty amino acids (AA) which have been found to occur in all proteins and for which genetic codon exits.
Lipids are broadly classified (modified from Bloor) into simple, complex, derived and miscellaneous lipids, which are further subdivided. found in cell membranes, cholesterol, blood cells, and in the brain
Explanation:
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The answer is A- sperm and egg. gametes are reproductive cells in mammals, so sperm and egg would be the correct.
Answer: the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Explanation:
We know that; Gram negative bacteria looks pale reddish in color under a light microscope from Gram staining.
therefore
There are 30 red bacterial colonies counted.
1 mL of from tube 1 was removed and added to tube with 99 mL saline (tube 2) dilution is 1/100.
transferred volume into the plate is 1 mL.
Now, we have to determine the cfu/g Gram-negative bacteria in the fecal sample
Formula to calculate CFU/g bacteria in fecal sample is expressed as;
C = n/(s×d )
where C is concentration (CFU/g)
, n is number of colonies
, s is volume transferred to plate
, d is dilution factor.
so we substitute
C = 30 / ((1/100) × 1)
C = 30 / 0.01
C = 3000
C = 3.0 × 10^3
THERFERE, the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Answer:
D.
Explanation:
The reactants used in photosynthesis are H2O(water), CO2(carbon dioxide), and light(sunlight) energy. These are used to produce glucose for the plant and oxygen which is released.
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Answer:
If both parents are heterozygous in a monohybrid cross, the offspring will have a phenotypic ratio of 3:1. If both are heterozygous for both traits in a dihybrid cross, the phenotypic ratio will be 9:3:3:1.
