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Vedmedyk [2.9K]

3 years ago

10

Mr. Gordon weighs 205 pounds . Multiply his earth weight by 0.91 to find out how much he would weigh on the planet Venus. What i

s the difference between mr. Gordon's earth weight and his weight on Venus

1 answer:

Savatey [412]3 years ago

5 0

When you multiply 205 by 0.91 you get 186.55 and 205 minus 186.55 is 18.45

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Here is a list of numbers:<br> 0, 10,-18, 7, -14,-7,7,-14,13,0<br> State the median.

Alex777 [14]

-21/2 which in decimals would be -10.5. The actual numbers would be -14 and -7 and the median

4 0

3 years ago

W(x)=9x+8,evaluate w(5)

natima [27]

Use the substitution method

w(x)=9x+8

w(5)=9(5)+8

Do the parenthesis first then add because of using PEMDAS

P= Parentheses

E= Exponents

M= Multiplication

D= Division

A= Addition

S= Subtraction

45+8

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Answer: w(5)=53

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o-na [289]

Answer:

a) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401$

And rounded up we have that n=2401

b) $n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22$

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

Part a

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior information about the population proportion we can use ase estimator $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401$

And rounded up we have that n=2401

Part b

For thi case the estimator for p is $\hat p =0.07$

$n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22$

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0

3 years ago

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lisabon 2012 [21]

Answer:

a) c) μ = 16.4.

b) d) μ > 16.4.

c) a) μ < 16.4.

d) c) μ ≠ 16.4.

e) d) right; left; both.

Step-by-step explanation:

Question a:

Test if it is getting worse, so at the alternative hypothesis we test if the mean is of greater than 16.4 inches, but at the null hypothesis we test if it is still of 16.4 options, so option C.

Question b:

At the alternative hypothesis we test if the mean is of greater than 16.4 inches, as said above, so the answer is given by option d.

Question c:

Dying down, so if the mean is lower than 16.4 inches, so option a.

Question d:

Don't know, so just test if it is different, which includes both lower or greater, so the correct answer is given by option c.

Question e:

Test if more -> right, so on question b) is a right tailed test.

Test if less -> left, so on question c) is a left tailed test.

Different -> both sides, so on question d) it is a two-tailed test.

Thus the correct answer is given by option d.

3 0

3 years ago