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3 years ago

Help me anyone please

Mathematics

1 answer:

sergeinik [125]3 years ago

8 0

X< or equal to 8 because x is less than 8 or equal to 8 and x is any number that could be 8 or any number that is less.

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What exactly are prime numbers?

nignag [31]

Prime numbers are numbers that only have a factor of one and its self.

4 0

3 years ago

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Help to answer this question?

rosijanka [135]

Answer:

No, Victoria doesn't have enough. She doesn't have enough because 15% off of 139.99 is 118.99. But then their is a 7% sales tax. So once you add the sales tax you get $127.32 and her max is $125.

Step-by-step explanation:

4 0

3 years ago

⦁ Evaluate ⦁ 6! ⦁ 8P5 ⦁ 12C4

lisabon 2012 [21]

6! = 6 * 5 *4*3*2*1 =720

8p5 = 8*7*6*5*4 = 6720

12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495

7 0

3 years ago

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Sloan [31]

Answer:

Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

Step-by-step explanation:

We need to find sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$

Finding sum of $\frac{7}{x^2-4}$ and $\frac{2}{x+2}$ :

$\frac{7x}{x^2-4}+\frac{2}{x+2}$

We know that $x^2-4 =(x+2)(x-2)$

Replacing x^2-4

$\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}$

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

$=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}$

So, Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

6 0

2 years ago

PLS HELP ME WITH THIS!!!!!! HOW DID THEY GET 80ft^2

noname [10]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Determine the surface area of the right square pyramid.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where

b = base of the right square pyramid
l = slant height of the right square pyramid.

In the given figure,

base (b) = 4 ft.
slant height (l) = 8 ft.

Now, let's substitute the values of b & l in the formula & solve it :-

$\sf \: {b}^{2} + 2bl \\ = \sf \: {4}^{2} + 2 \times 4 \times 8 \\ = \sf \: 16 + 8 \times 8 \\ = \sf \: 16 + 64 \\ = \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}$

So, the surface area of the right square pyramid is 80 ft².

7 0

3 years ago