Answer: B
Step-by-step explanation:
Multiply U and V:
Therefore, the correct answer is B
Multiples of 11 between 1 and 30:
11, 22
So there are 2 numbers that are multiples of 11 in the bin. There are a total of 30 cards, so the probability is written as 2/30. Or we can simplify it to 1/15.
For the next question:
There are a total of 3 + 8 = 11 balls in the bag.
The probability of choosing a red ball is 3/11.
The probability of choosing a green ball is 8/11.
Multiply the three fractions:
3/11 * 3/11 * 8/11 = 72/1331
So the probability is 72/1331.
For the last question:
A standard deck of cards has 52 cards.
There are 4 queens and 4 kings in the deck.
Probability of choosing a queen is 4/52, and the probability of choosing a king AFTER you already chose a queen is 4/51.
Multiply the two fractions:
4/52 * 4/51 = 16/2652
So the probability is 16/2652 or 4/663
Answer:
y = 2x + 1 ;
y - 3 = - 3(x - 1) ; y = - 3x + 6 ;
Independent ;
(1, 3)
Step-by-step explanation:
Given the data:
Sidewalk 1:
x __ y
2 _ 5
0 _ 1
Sidewalk 2:
x __ y
1 _ 3
3 _ -3
Equation for sidewalk 1 in slope - intercept form:
Slope intercept form:
y = mx + c
c = intercept ; m = slope
m = (change in y / change in x)
m = (1 - 5) / (0 - 2) = - 4 / - 2 = 2
Y intercept ; value of y when x = 0
(0, 1) ; y = 1
Hence, c = 1
y = 2x + 1
Sidewalk 2:
Point slope form:
y - y1 = m(x - x1)
m = slope
m = = (-3 - 3) / (3 - 1) = - 6/2 = - 3
Point (x1, y1) = (1, 3)
y - 3 = - 3(x - 1)
To slope intercept form:
y - 3 = - 3(x - 1)
y - 3 = - 3x + 3
y = - 3x + 3 + 3
y = - 3x + 6
Since the slope of both lines are different, intersection will be at single point and will have a single solution. This makes it independent.
Using substitution method :
y = 2x + 1 - - - (1)
y = - 3x + 6 - - - (2)
Substitute (1) into (2)
2x + 1 = - 3x + 6
2x + 3x = 6 - 1
5x = 5
x = 1
From (1)
y = 2(1) + 1
y = 2 + 1
y = 3
Coordinate of the point of intersection = (1, 3)
The prime numbers are 17, 19, 23, 29, 31, and 37
Prime number - A number thats only factors are 1 and itself
The answers are-
XP=YP for an acute triangle
YP=ZP for an obtuse triangle
XP=YP For an obtuse triangle
