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iVinArrow [24]
3 years ago
14

How do I do this problem ??

Mathematics
1 answer:
kati45 [8]3 years ago
3 0
See attached picture for solution:

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Divide. write in smplest form 12÷2 2/7
Anit [1.1K]
I hope this helps you

3 0
3 years ago
What is the solution to the equation below?<br> 12 + square root 1 - 5x = 18
GrogVix [38]

Answer:

-1

Step-by-step explanation:

Square root 1 is 1. Add that to the 12 to get 13. Subtract 13 from both sides to get: -5x = 5. Divide both sides by -5 to get your answer: -1

5 0
3 years ago
Read 2 more answers
What is the value of square root 30 is between witch two integers
inn [45]

Answer:

b

Step-by-step explanation:

because

8 0
3 years ago
What does this equal to?
lesantik [10]

Answer:

x = 14

y = 7

z = 22

Step-by-step explanation:

x = # of cucumbers

y = # zucchini

z = # tomatoes

x + y + z = 43

2y = x  or  y = x/2

x + 8 = z

x + x/2 + x + 8 = 43

2x + x/2 = 35

4x + x = 70

5x = 70

x = 14

2y = 14

y = 7

14 + 8 = z

z = 22

Check if these variables are right:

14 + 7 + 22 = 43 ✔️

6 0
2 years ago
Find an equation of the circle that has center (-4,3) and passes through (6,-4).
kumpel [21]

Answer:

(x+4)^2+(y-3)^2=149

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center of the circle and r is the radius of the circle.

Given that (h,k)\rightarrow(-4,3) and it passes (6,-4), their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-4-3)^2+(6-(-4))^2}\\\\d=\sqrt{(-7)^2+10^2}\\\\d=\sqrt{49+100}\\\\d=\sqrt{149}

Therefore, if the length of the radius is r=\sqrt{149} units, then r^2=149, making the final equation of the circle (x+4)^2+(y-3)^2=149

5 0
2 years ago
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