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3 years ago

Why is it impossible to list the set of rational numbers using the roster method?

1 answer:

dsp733 years ago

5 0

It is impossible to list the set of rational numbers using the roster method because the set of rational numbers is uncountable/inumerable.

There is no way to list all the members of the set of rational numbers.

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Consider the expression 16a + 4c.

kari74 [83]

The answer would -38

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2 years ago

Determine the domain and range of the relation {(3, 8), (3, 2), (5, 2), (6, 1), (9,1)} I don't understand domain and range. Help

VLD [36.1K]

Answer:

The domain is the first number in each set so like the domain is: 3,5,6,9

6 0

2 years ago

A line passes through the point (2,3) and has a slope of 0, what equation of the line?

Andru [333]

Answer: B

Step-by-step explanation: put the points on a graph

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2 years ago

Please help 30 points

Ulleksa [173]

Replace x and y with the given values:

2(1/8 + 4) - (3/16*8)

Use distributive property:

1/4 + 8 - (3/16 * 8)

Simplify to get final answer:

8 1/4 - 1 1/2 = 6 3/4

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2 years ago

Read 2 more answers

What is the relationship between exponentials and logarithms? How can you use these to solve equations? Provide an example in yo

Sveta_85 [38]

Answer:

Exponentials and logarithms are inverses of each other.

Step-by-step explanation:

Exponentials and logarithms are inverses of each other.

For logarithmic function:

Domain = $\left ( 0,\infty \right )$ , Range = $\left ( -\infty ,\infty \right )$

Vertical asymptote is y - axis.

x - intercept is (1,0)

For exponential function:

Domain = $\left ( -\infty ,\infty \right )$ , Range = $\left ( 0,\infty \right )$

Horizontal asymptote is x - axis.

y- intercept is (0,1)

Both exponential and logarithmic functions are increasing.

For example:

Solve: $\log x=\frac{\log 5+\log 3}{\log 3^2}$

$\log x=\frac{\log 5+\log 3}{\log 3^2}\\\log x=\frac{\log (5\times 3)}{2\log 3}\,\,\left \{ \because \log (ab)=\log a+\log b\,,\,\log a^b=b\log a \right \}\\=\frac{\log 15}{2\log 3}$

$\Rightarrow \log x=\frac{\log 15}{2\log 3}\\\Rightarrow x=e^{\frac{\log 15}{2\log 3}}\,\,\left \{ \because \log x=y\Rightarrow x=e^y \right \}$

4 0

2 years ago