All categories

3 years ago

Why is it impossible to list the set of rational numbers using the roster method?

1 answer:

dsp733 years ago

5 0

It is impossible to list the set of rational numbers using the roster method because the set of rational numbers is uncountable/inumerable.

There is no way to list all the members of the set of rational numbers.

You might be interested in

Which part of the expression is a factor 7(x+8) A. 21 B.8 C. 3x D. 7

Sever21 [200]

It is 7. None of the other ones fit at all

8 0

3 years ago

Read 2 more answers

A digit in the hundredths place has ten times the value of the same digit in the thousands place

bagirrra123 [75]

That is true very good

5 0

4 years ago

Jackie is selling smoothies at a school fair. She starts the day with $15 in her cash box to provide change to her customers. If

Liula [17]

Answer:

ىر سيىخرسىي ىتسيرىتسهارسيخهكتر يسرلاتزسنيى يتريزىيسئرتسئرة سينرةظسئر سظرى ئمرىسنرمسيىمر سئرىسئنرتىئسر ؟

8 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

We can conclude that the change to the face 3 affects the value of P(Odd Number)

7 0

3 years ago

Write the percent as a mixed number in simplest form. 168%

vladimir2022 [97]

Answer:

1 and 17/25

Step-by-step explanation:

First, you make it into a fraction. So because percents are out of 100, it would be 168/100. Then, you take 100 out of it to get a mixed number, 1 and 68/100, and then simplify 68/100 by dividing both sides by the greatest common factor, which is 4. 68/100÷4=17/25. The answer would be 1 and 17/25.

(hope this helps :P)

4 0

3 years ago