The area of the rectangle formed by the intersection of the plane and cube is 
The diagram of the cube and the cutting plane is shown in the figure.
Since the cube has a volume of 
, the sides are 
each.
From the diagram, the red rectangle is the rectangle formed from the intersection of the plane and the cube. It has an area given by
and, using Pythagoras' theorem,
Substituting the value of 
into the formula for 
The area of the rectangle formed by the intersection of the plane and cube is
Learn more about areas formed from cubes here: brainly.com/question/25636539
Based on the calculations, the pressure inside this droplet is equal to 2,909.35 kPa.
<u>Given the following data:</u>
- Surface tension = 0.00518 lbf/ft to N/m = 0.00702 N/m.
- Atmospheric pressure = 14.7psia to kPa = 101.35 kPa.
- Diameter = 0.01 mm to m = 0.00001 m.
Radius, r = 
= 0.000005 m.
<h3>How to determine the pressure inside a droplet.</h3>
For a droplet with only one surface, its pressure is given by this formula:
Substituting the given parameters into the formula, we have;
Inside pressure = 2,909.35 kPa.
Read more on pressure here: brainly.com/question/24827501
Based on the graph given, it can be deduced from the computation that the value of y will be -8.
Point C is given as (-10 , -2) and D = (10 , 6)
The Slope of line CD = ( 6 - (-2) /( 10 - (-10) = 8/20 = 2/5
Since EF is parallel to line CD
, the slope of EF = 2/5
Equation y = (2/5)x + c
5y = 2x + 5c
It passes through F ( 6 , -4)
= 5(-4) = 2*6 + 5c
= -20 = 12 + 5c
5c = -32
5y = 2x - 32
Point E ( - 4 , y)
5y = 2(-4) - 32
5y = -8 - 32
5y = -40
y = -8
Therefore, the value of y is -8.
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brainly.com/question/19040584
Answer:
Of course its not your love for the athlete! The problem might be that you think you are nice but could be doing something wrong. try talking to someone that isnt nice back and ask what do you not like about me or something like that.
Explanation:
