Question

Escherichia coli cells are about 2.65 μm long and 0.480 μm in diameter. Calculate the volume of an E. coli cell, assuming the cell to be cylindrical in shape.

Answer 1

Answer:

4.7953 x 10⁻¹⁹ m³

Step-by-step explanation:

Length of the Escherichia coli cell (L) = 2.65 x 10⁻⁶ m

Diameter of the Escherichia coli  cell (D) = 0.480 x 10⁻⁶ m

The volume of cylinder in given by:

$V= \frac{\pi D^2}{4}*L \\V= \frac{\pi (0.480*10^{-6})^2}{4}*2.65*10^{-6}\\V= 4.7953*10^{-19} m^3$

The volume of an E. coli cell is 4.7953 x 10⁻¹⁹ m³.