Let 

. Then 

. By convention, every non-zero integer 

 divides 0, so 

.
Suppose this relation holds for 

, i.e. 

. We then hope to show it must also hold for 

.
You have

We assumed that 

, and it's clear that 

 because 

 is a multiple of 3. This means the remainder upon divides 

 must be 0, and therefore the relation holds for 

. This proves the statement.
 
        
        
        
Answer: 3^6 so D or C
Step-by-step explanation:
When dividing two squares, you minus the number
 
        
                    
             
        
        
        
Answer:
16 fish
Step-by-step explanation:
 
        
             
        
        
        
Answer:
Step-by-step explanation:
start with 760 dollars. find 4% of that amount then add that % plus the starting amount 5 diffrent times.