Let

. Then

. By convention, every non-zero integer

divides 0, so

.
Suppose this relation holds for

, i.e.

. We then hope to show it must also hold for

.
You have

We assumed that

, and it's clear that

because

is a multiple of 3. This means the remainder upon divides

must be 0, and therefore the relation holds for

. This proves the statement.
Answer: 3^6 so D or C
Step-by-step explanation:
When dividing two squares, you minus the number
Answer:
16 fish
Step-by-step explanation:
Answer:
Step-by-step explanation:
start with 760 dollars. find 4% of that amount then add that % plus the starting amount 5 diffrent times.