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shtirl [24]
4 years ago
11

What is (4c-d+0.2)^2-10c; c=3.1, d=4.6​

Mathematics
2 answers:
yuradex [85]4 years ago
8 0

Good evening ,

______

Answer:

(4c-d+0.2)² - 10c = 33

___________________

Step-by-step explanation:

(4c-d+0.2)^2-10c

c=3.1, d=4.6​

(4(3.1) - 4.6 + 0.2)² - 10(3.1) = (12.4 - 4.6 + 0.2)² - 31 = (7.8 + 0.2)² -31 = 8² - 31 = 64-31 =33.

:)

Dafna1 [17]4 years ago
5 0

Answer: The value of the above expression is 18.

Step-by-step explanation:

Since we have given that

(4c-d+0.2)^2-10c

Here, c = 3.1

d = 4.6

Put the value in the above expression:

(4\times 3.1-4.6+0.2)^2-10\times 4.6\\\\=(12.4-4.6+0.2)^2-46\\\\=8^2-46\\\\=64-46\\\\=18

Hence, the value of the above expression is 18.

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Answer:

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Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

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Now, find the margin of error M as such

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In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{20}{\sqrt{90}} = 3.4

The lower end of the interval is the sample mean subtracted by M. So it is 122 - 3.4 = $118.6

The upper end of the interval is the sample mean added to M. So it is 122 + 3.4 = $125.4

The 90% confidence interval for the true mean daily wage of all union workers in the industry is ($118.6, $125.4). The lower limit is $118.6 and the upper limit is $125.4.

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suppose that f(x) = -ax + b

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where b and c are different numbers (because if b and c are equal, we have that g(x) and f(x) represent the same line)

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