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Len [333]
3 years ago
14

Find the sum of the polynomials.x² + 5x² + 9x - 69x² - 4x + 6​

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

15x^2+5x

Step-by-step explanation:

igomit [66]3 years ago
4 0

Answer:

15x^2+5x

Step-by-step explanation:

If adding both together, this is your answer.

Hope this helps!

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1. Using property, simplify:
lorasvet [3.4K]

Answer:

You can only solve this using BODMAS

Step-by-step explanation:

You solve them in this order

B=Brackets

O=Orders

D=Division

M=Multiplication

A=Addition

S=Subtraction

5 0
3 years ago
If you answer this right you get brainliest <3 ;)
krok68 [10]

Answer:

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8 0
3 years ago
Suppose that pulse rates among healthy adults are normally distributed with a mean of 80 beats/second and a standard deviation o
olga_2 [115]

Answer:

0.3520

Step-by-step explanation:

We have been given that the pulse rates among healthy adults are normally distributed with a mean of 80 beats/second and a standard deviation of 8 beats/second. We are asked to find the proportion of healthy adults have pulse rates that are more than 83 beats/sec.

First of all, we will find z-score corresponding to sample score of 83 as:

z=\frac{x-\mu}{\sigma}, where,

z = Z-score,

x = Sample score,

\mu = Mean,

\sigma = Standard deviation.

Upon substituting our given values in z-score formula, we will get:

z=\frac{83-80}{8}=\frac{3}{8}=0.375\approx 0.38

Now, we need to find the probability that a z-score is greater than 0.38.

Using formula P(z>a)=1-P(z, we will get:

P(z>0.38)=1-P(z

Using normal distribution table, we will get:    

P(z>0.38)=1-0.64803

P(z>0.38)=0.35197

P(z>0.38)\approx 0.3520

Therefore, 0.3520 of healthy adults have pulse rates that are more than 83 beats/sec.

8 0
4 years ago
If there are 5 family members all exchanging gifts, how many gifts are exchanged?
leonid [27]
I think 20 gifts would be exchanged because each family member has to exchange 1 gift to everyone
4 0
3 years ago
How do I solve this equation?
Gnom [1K]

2x(4-x)^{-1/2}-3(4-x)^{1/2}=(4-x)^{-1/2}\bigg(2x-3(4-x)\bigg)

We effectively rewrite the equation as

\dfrac{5x-12}{(4-x)^{1/2}}=0

In order for the LHS to be defined, we need to restrict 4-x>0, or x. Now, the LHS will vanish when the numerator is 0, which happens for

5x-12=0\implies5x=12\implies x=\dfrac{12}5

This value is indeed smaller than 4, so the solution is x=\dfrac{12}5.

8 0
3 years ago
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