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aalyn [17]
3 years ago
12

There are five identical blue books, two identical green books, and three identical black books. How many different patterns can

the books be arranged on a shelf?
Mathematics
1 answer:
dsp733 years ago
8 0

Answer:

2520 patterns

Step-by-step explanation:

In 'n' 10!  ways, books can be arranged. But, there are also 5! permutation of blue books 'n1', 2! permutation of identical green books 'n2', and 3! permutation identical black books 'n3'.

Therefore, for non identical arrangements:

\frac{n!}{n1!n2!n3!}

\frac{10!}{5!2!3!} = 2520

Therefore, the books can be arranged on a shelf in 2520 patterns

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Question 4
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I just solved a question similar to this

Let's understand it

It's saying she got 660 or it is that her weekly pay is 660

So now let weekly pay which is P be 660

Hence the formulae is given

It's 480 + 18 (h – 30) = 660

Now its just boring calculation

If you mark it brainleist I will do the calculation for you wink wink

Never mind

480 + 18 (h – 30) = 660

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