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MAXImum [283]
3 years ago
10

The Transmission Control Protocol (TCP) splits each message into multiple packets. It's possible for packets from the same messa

ge to arrive out of order.Which field in the IP packet helps computers put the packets in the original order?
Computers and Technology
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

The header file

Explanation:

The 'header' of a packet contains two important information about the data being sent over a network,  number indicating the ordering of all the packets (This ensures that the packets are re-ordered corrected upon arrival at the destination). and information about the total number of packets that the data has been split into, this helps at the destination to know if all packets has arrived, or delayed or lost

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Danny is editing the text content of a single page on a website he created a year ago. What part of the tag would he have to upd
Verdich [7]
<h2>"<lastmod>" is the right choice for the given scenario</h2>

Explanation:

<update> This tag does not belong to <URL> tag of the site map. Hence this option goes invalid.

<lastmod> This gives details of the date and time when the website content was changed. It will be in "W3C Date time format". This may omit time at times. This is the write answer.

<loc> This contains the URL of the web page.

<changefreq>: How frequently the "web page is likely to get modified". The  values which it accepts are: "monthly, always , daily , weekly ,hourly, yearly , never"

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3 years ago
Customer A with a Bronze service level package calls in a Critical System Failure at 9:00 AM. Customer B with a Silver service l
inysia [295]
This question depends on what the service level packages have to offer as an agreement. Does this question come with a list of what the service levels have to offer?
4 0
3 years ago
5. Create a variety of test cases focusing on the sorting algorithm, such as the final element is the smallest, the entire set i
andrew11 [14]

Answer:

// C code

// This code will compute the values of the sales ticket sales for concerts

#include <stdio.h>

#define MAXN 100 // max characters in a group/concert name

#define MAXG 50 // max concerts/groups

#define MAXC 3 //max categories

char group [MAXG][MAXN];

int fans [MAXG][MAXC];

float prices [MAXC];

float sales [MAXG];

int count = 0;

void printArray () {

printf ("%15s%5s%5s%5s%10s\n",

"Concert", "s1", "s2", "s3","Sales");

for (int i = 0; i < count; i++) {

printf ("%15s", group [i]);

for (int j = 0; j < MAXC; j++) {

printf ("%5d", fans[i][j]);

} // end for each category

printf ("%10.2f\n", sales [i]);

} // end for each group

} // end function printArray

void computeSales () {

for (int i = 0; i < count; i++) {

sales [i] = 0;

for (int j = 0; j < MAXC; j++) {

sales [i] += prices [j] * fans [i][j];

} // end for each category

} // end for each group

} // end function computeSales

// ***** totalSales ****

void totalSales()

{

float tsales;

for(int i = 0; i <= MAXC; i++){

tsales += sales [i];

}

printf("\n\t\tThe total sales are: $%.2f\n",tsales);

}

// ***********************************

void switchRows (int m, int n) {

char tc;

int ti;

float v;

// printf ("Switching %d with %d\n", m, n);

for (int i = 0; i < MAXN; i++) {

tc = group [m][i];

group [m][i] = group [n][i];

group [n][i] = tc;

} // end for each character in a group name

for (int i = 0; i < MAXC; i++) {

ti = fans [m][i];

fans [m][i] = fans [n][i];

fans [n][i] = ti;

} // end for each fan category

v = sales [m];

sales [m] = sales [n];

sales [n] = v;

} // end switch

int findMinSales (int m) {

float min = sales [m];

int target = m;

for (int i = m+1; i < count; i++)

if (sales [i] < min) {

min = sales [i];

target = i;

} // end new max found

return target;

} // end function findMinSales

void sortBySales () {

int target;

for (int i = 0; i < count; i++) {

target = findMinSales (i);

if (target > i)

switchRows (i, target);

} // for each concert

} // end function sortBySales

//**********sort by fans*************

int minFans (int b) {

float min = fans [b][0];

int target = b;

for (int i = b; i < count; i++)

if (fans [i][0] < min) {

min = fans [i][0];

target = i;

} // end new max found

return target;

}

void sortByFans () {

int target = 0;

//int result;

 

for (int i = 0; i < count; i++) {

target = minFans(i);

if (target > i)

//result = target;    

switchRows (i,target);

 

}

}

//********************************

void getData () {

// for (int i = 0; i < MAXG; i++) sales [i] = 0;

printf ("\nEnter ticket prices in each of %d cateogories: ", MAXC);

for (int i = 0; i < MAXC; i++)

scanf ("%f", &prices [i]);

printf ("-- Enter group and fans in %d categories\n", MAXC);

printf (" . to finish entries:\n");

for (int i = 0; i < MAXG; i++) {

scanf ("%s", group[i]);

if (group [i][0] == '.')

break;

count++;

for (int j = 0; j < MAXC; j++)

scanf ("%d", &fans[i][j]);

} // end for each group

} // end function getData

int main(void) {

getData ();

computeSales ();

printArray ();

printf ("\n --- Sorted sales ---\n");

sortBySales ();

printArray ();

totalSales ();

printf("--- sorted by fans ---\n");

sortByFans ();

printArray ();

totalSales ();

printf("\t\t ... Bye ...\n");

return 0;

}

7 0
3 years ago
When computer network are joined together they form a bigger network called the​
Airida [17]

Answer:

A WAN can be one large network or can consist of two or more lans connected together. The Internet is the world's largest wan.

Explanation:

8 0
3 years ago
Which one of the following media is most resistant to EMI?
natali 33 [55]

Answer:

D - Fiber-optic Cables

Explanation:

Electromagnetic interference affects cables made from different metals and can corrupt the data running through them. However, Fiber-optic cables are constructed from glass (non-metallic) and transmit pulses of light as signals to transfer data, this means that the cables are most resistant and not susceptible to EMI.

5 0
3 years ago
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