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Svetllana [295]
3 years ago
5

75% of 48is what number? 22 is what percent of 40?

Mathematics
2 answers:
tigry1 [53]3 years ago
6 0
75%of 48=.75x48=36

40/100=22/x
40 (x)=22 (100)
40x=2200
40/40x=2200/40
x=55%
OlgaM077 [116]3 years ago
4 0
36 is 75% of 48

22 out of 40 is 55%
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Write the ratio of the area of a circle with radius r to the circumference of the same circle
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Answer:

\frac{r}{2\pi r} =\frac{1}{2\pi }

Step-by-step explanation:

A ratio is a comparison of two quantities and can be written in several forms including fractions. It is most commonly written in fraction form or a:b.

To write a ratio, we count the number of each quantity we are comparing or use the variable for that quantity. We write radius:circumference. Recall, the circumference of a circle can be found using \pi d or 2\pi r.

We write r: \pi d  or r:2\pi r.

We can also write in fraction form:

\frac{r}{\pi d} or \frac{r}{2\pi r} =\frac{1}{2\pi }


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3 years ago
The y-intercept of the line whose equation is 2x + y = 4 is -2 2 4
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AlekseyPX

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Step-by-step explanation:

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3 years ago
A can is 4 inches wide and 8 inches tall. To the nearest whole number, what is the area of a label that wraps around the can if
Yakvenalex [24]

Answer:

The area of a label is 62.8\ in^{2}

Step-by-step explanation:

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5 0
3 years ago
The question is in the picture please help
ahrayia [7]

Answer:

Claim 2

Step-by-step explanation:

The Inscribed Angle Theorem* tells you ...

... ∠RPQ = 1/2·∠ROQ

The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.

... 2·∠RPQ = ∠ROQ

The symmetric property of equality says you can rearrange this to ...

... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ

_____

* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.

You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.

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3 years ago
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