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antoniya [11.8K]
3 years ago
10

What is the axis of symmetry for f(x) = −5x2 − 20x − 10

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0

Answer:

x=  -2 is the axis of symmetry for f(x) = -5x^2-20x-10

Step-by-step explanation:

A quadratic equation is in the form of y =ax^2+bx+c .......[1],

then the axis of symmetry is given by:-

x = -\frac{b}{2a}                   ....[2]

As per the statement:

f(x) = -5x^2-20x-10

On comparing with equation [1] we have;

a = -5, b = -20 and c = -10

Substitute these values in [2] we have;

x = -\frac{-20}{2 \cdot (-5)}

⇒x = -\frac{-20}{-10}

Simplify:

x =  -2

Therefore, the axis of symmetry for the given function is, x= -2.

Tasya [4]3 years ago
6 0
<span>For this case we have the following function:
</span> f(x) = -5x^2 - 20x - 10&#10;
<span> To find the axis of symmetry, the first thing to do is to derive the function.
 We have then:
</span> f '(x) = -10x - 20 &#10;
<span> Equaling zero we have:
</span> -10x - 20 = 0 &#10;
<span> We clear the value of x.
 We have then:
</span> -10x = 20 &#10;&#10;x = -20/10 &#10;&#10;x = -2 &#10;
<span> Answer:
 The axis of symmetry is given by:
 x = -2</span>
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