We either need to see a picture of this and/or get more information about the measurements of the triangle. In general, the area outside of the triangle will be the area of the semi-circle minus the area of the triangle itself, or: 1/2*49*3.14 - 1/2 b*h of the triangle. That first part, which is the area of the semi-circle, works out to 76.93 So based on the info we have, it becomes 76.93 - 1/2*b*h of the triangle = area outside of triangle.
Speed= distance/time
= 1110/15
= 74 feet per second
You find the answer through the Pythagorean theorem
a^2 + b^2 = c^2 a & b are the legs and c is the hypotenuse
a = 40
b = ?
c = 41
40^2 + b^2 = 41^2
1600 + b^2 = 1681
b^2 = 1681 - 1600
b^2 = 81
b = 9
the length of the other leg is 9
i hope you found this helpful!
