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Marina CMI [18]
2 years ago
7

HELP ASAP WIL GIVE BRAINLIEST What is the interquartile range of the data set? {76, 22, 38, 95, 75, 60, 62, 92}

Mathematics
1 answer:
Jet001 [13]2 years ago
4 0
65 would be your answer take all 8 numbers add them up and divide by 8
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ki77a [65]

Answer: how many hours is she working

Step-by-step explanation:

8 0
3 years ago
Write as an algebraic expression
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

well the answer to 14 is 7 and for 16 its 6

5 0
2 years ago
Plz help asappppppppp!!!
MAVERICK [17]

Answer:

10, 22, 48.4, 106.48, 234.256

Step-by-step explanation:

The first term is already given it is 10.

The second term is the first term times 2.2.

10×2.2=22

The second term is 22.

The third term is the second term times 2.2.

22×2.2=48.4

The third term is 48.4.

The fourth term is the third term times 2.2.

48.4×2.2=106.48

The fourth term is 106.48.

The fifth term is the fourth term times 2.2.

106.48×2.2=234.256

The fifth term is 234.256.

8 0
2 years ago
James used a substitution to solve this system of equations. Which equation could be a result of his first step? 2x+3y=12 y=x+1.
Blizzard [7]

Answer:

x = 1.5

y = 3

Step-by-step explanation:

to solve this system of equation using the substitution methods we say let

2x+3y=12................................... equation 1

y=x+1.5..................................... equation 2

substitute equation 2  into equation 1

2x+3y=12................................... equation 1

2x + 3( x + 1.5) = 12

2x + 3x + 4.5 = 12

5x + 4.5 = 12

collect the like terms

5x = 12 - 4.5

5x = 7.5

divide both sides by the coefficient of x which is 5

5x/5 = 7.5/5

x = 1.5

put x = 1.5 into equation 2

y=x+1.5..................................... equation 2

y = 1.5 + 1.5

y = 3

therefore the value of x = 1.5 and y = 3 respectively.

5 0
3 years ago
NEED HELP!! PLEASE PLEASE
Bezzdna [24]

Answer:

The answer is A

Step-by-step explanation:

hope this helps,

If you like my answer please give brainliest,

Happy Holidays!

6 0
3 years ago
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