Answer:
I believe that the answer is B
Answer: D.) This is an example of inductive reasoning because a general conclusion is reached based on a specific example,
Step-by-step explanation: Inductive reasoning simply refers to making conclusion about a specific subject or topic from patterns or insights derived from related examples. In the scenario above, the conclusion reached encompasses the overall full time 4 years college student. However, this conclusion was inferred based on a specific example comprising of only a randomized sample of 1200 full time 4 years college students in 100 campuses. random. The example failed to incorporate every student, Hence, the conclusion is induced as the choice of a sample of students may not convey the choice or decision of all.
Deductive reasoning meanwhile follows that a generally established fact is used to make conclusion about a specific example.

<h2>
Explanation:</h2>
Here we have the following expression:

So we need to simplify that radical expression. By property of radicals we know that:
![\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D%3D%5Csqrt%5Bn%5D%7Bab%7D)
So:

The prime factorization of 22968 is:

Hence:

By property:
![\sqrt[n]{a^n}=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da)
So:

Finally:

<h2>Learn more:</h2>
Radical expressions: brainly.com/question/13452541
#LearnWithBrainly
Answer:
131.1 in^2
Step-by-step explanation:
a=πr^2
<h3>
<u>Correct Question :- </u></h3>


(a) 0
(b) 8000
(c) 8080
(d) 16000

Given that

We know


And


Also, given that


and

Now, Consider





![\sf \: = 20\bigg[ {a}^{2} + {b}^{2} + {c}^{2} + {d}^{2}\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7Ba%7D%5E%7B2%7D%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%2B%20%7Bc%7D%5E%7B2%7D%20%2B%20%20%7Bd%7D%5E%7B2%7D%5Cbigg%5D)
We know,

So, using this, we get
![\sf \: = 20\bigg[ {(a + b)}^{2} - 2ab + {(c + d)}^{2} - 2cd\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7B%28a%20%2B%20b%29%7D%5E%7B2%7D%20-%202ab%20%2B%20%20%7B%28c%20%2B%20d%29%7D%5E%7B2%7D%20-%202cd%5Cbigg%5D)
![\sf \: = 20\bigg[ {( - 20)}^{2} + 2(2020) + {(20)}^{2} - 2(2020)\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7B%28%20-%2020%29%7D%5E%7B2%7D%20%2B%20%202%282020%29%20%2B%20%20%7B%2820%29%7D%5E%7B2%7D%20-%202%282020%29%5Cbigg%5D)
![\sf \: = 20\bigg[ 400 + 400\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20400%20%2B%20400%5Cbigg%5D)
![\sf \: = 20\bigg[ 800\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20800%5Cbigg%5D)

Hence,

<em>So, option (d) is correct.</em>