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erik [133]
3 years ago
15

MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE reposting cause no one answered them

Mathematics
1 answer:
sveta [45]3 years ago
6 0

A

since the 3 is outside the radical then \sqrt{9} = 3, hence

x = 9

B

using the law of radicals

\sqrt{a} × \sqrt{b} = \sqrt{ab}

we can separate the factors as

\sqrt{24} × √x^{10} × √y^{5}

= 2\sqrt{6} x^{5}y^{5/2}

C

\sqrt{121} + \sqrt{50} = 11 + 5\sqrt{2}

D

\sqrt{20} × \sqrt{63}

= 2\sqrt{5} × 3\sqrt{7}

= 6\sqrt{35}




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charle [14.2K]

Answer:

-2x

Step-by-step explanation:

Graph

y > −2x + 3

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

y = mx + b

Find the values of m and b using the form y = mx + b. m = −2

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Slope: −2

intercept: (0, 3)

Graph a dashed line, then shade the area above the boundary line since y is greater than

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Step-by-step explanation:

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A radioactive substance decreases in the amount of grams by one-third each year. If the starting amount of the
katovenus [111]

Answer:

The sequence is geometric. The recursive formula is a_{n}=2/3a_{n-1}

Step-by-step explanation:

In order to solve this problem, you have to calculate the amount of the substance left after the end of each year to obtain a sequence and then you have to determine if the sequence is arithmetic or geometric.

The substance decreases by one-third each year, therefore:

After 1 year:

1452-\frac{1}{3}(1452)

Using 1452 as a common factor and solving the fraction:

1452(1-\frac{1}{3})=1452(\frac{2}{3})=968

You can notice that in general, after each year the amount of grams is the initial amount of the year multiplied by 2/3

After 2 years:

968(\frac{2}{3})=\frac{1936}{3}

After 3 years:

\frac{1936}{3}(\frac{2}{3})=\frac{3872}{9}

The sequence is:

1452,968,1936/3,3872/9....

In order to determine if the sequence is geometric, you have to calculate the ratio of two consecutive terms and see if the ratio is the same for all two consecutive terms. The ratio is obtained by dividing a term by the previous term.

The sequence is arithmetic if the difference of two consecutive terms is the same for all two consecutive terms.

-Calculating the ratio:

For the first and second terms:

968/1452=2/3

For the second and third terms:

1936/3 ÷ 968 = 2/3

In conclussion, the sequence is geometric because the ratio is common.

The recursive formula of a geometric sequence is given by:

a_{n}=ra_{n-1}

where an is the nth term, r is the common ratio and an-1 is the previous term.

In this case, r=2/3

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Tasya [4]

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