Question

MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE reposting cause no one answered them

Answer 1

A

since the 3 is outside the radical then $\sqrt{9}$ = 3, hence

x = 9

B

using the law of radicals

$\sqrt{a}$ × $\sqrt{b}$ = $\sqrt{ab}$

we can separate the factors as

$\sqrt{24}$ × √$x^{10}$ × √$y^{5}$

= 2$\sqrt{6}$ $x^{5}$$y^{5/2}$

C

$\sqrt{121}$ + $\sqrt{50}$ = 11 + 5$\sqrt{2}$

D

$\sqrt{20}$ × $\sqrt{63}$

= 2$\sqrt{5}$ × 3$\sqrt{7}$

= 6$\sqrt{35}$