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3 years ago

Please help and show all work. 15 points.

Mathematics

1 answer:

Triss [41]3 years ago

5 0

30 60 90 right triangle
if QR = 24 then the legs are 12 and 12√3

A = 1/2(18+6)(12) + 1/2(12)(12√3 )
A = 144 + 72√3

answer is A
144 + 72√3

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A function follows the rule y = -75 - 5x. When the function's output is 25, the equation is 25 = -75 - 5x. What is the function

svetlana [45]

Answer:

The function input is -20 when the output is 25

Step-by-step explanation:

we have

$y=-75-5x$

where

y is the dependent variable or output

x is the independent variable or input

If the output is 25

then

y=25

substitute

$25=-75-5x$

Solve for the function input is the same that solve for x

Isolate the variable x

Adds 5x both sides

$25+5x=-75-5x+5x$

$25+5x=-75$

subtract 25 both sides

$25+5x-25=-75-25$

$5x=-100$

Divide by 5 both sides

$x=-20$

therefore

The function input is -20 when the output is 25

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Step-by-step explanation:

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Megan hiked 15.12 miles in 6.3 hours. If Megan hiked the same number of miles each hour , how many miles did she hike each hour?

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To find how many miles per hour, we divide the number of miles hiked by the number of hours it took to hike them.

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4 years ago

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3 years ago

HELP ASAP photo attached

ankoles [38]

Answer:

D. undefined

General Formulas and Concepts:

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Trig Derivative: $\displaystyle \frac{d}{dx}[sinu] = u'cosu$

Derivatives of Parametrics: $\displaystyle \frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{dx}{dt} = 5$

$\displaystyle \frac{dy}{dt} = sin(t^2)$

Step 2: Differentiate

[x Derivative] Basic Power Rule: $\displaystyle \frac{d^2x}{dt^2} = 0$
[y Derivative] Trig Derivative [Chain Rule]: $\displaystyle \frac{d^2y}{dt^2} = cos(t^2) \cdot \frac{d}{dt}[t^2]$
[y Derivative] Basic Power Rule: $\displaystyle \frac{d^2y}{dt^2} = cos(t^2) \cdot 2t^{2 - 1}$
[y Derivative] Simplify: $\displaystyle \frac{d^2y}{dt^2} = 2tcos(t^2)$
[Derivative] Rewrite: $\displaystyle \frac{d^2y}{dx^2} = \frac{2tcos(t^2)}{0}$

Anything divided by 0 is undefined.

Topic: AP Calculus BC (Calculus I/II)

Unit: Differentiation with Parametrics

Book: College Calculus 10e

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3 years ago