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statuscvo [17]
3 years ago
13

Emma spent $35.22 on 3 dozen bagels and a gallon of iced tea. The price of the gallon of iced tea was $5.25. The following equat

ion can be used to find d, the price of each dozen of bagels.
3d + 5.25 = 35.22

What is the price of the bagels?
Mathematics
1 answer:
amm18123 years ago
4 0

Answer:

9.99

Step-by-step explanation:

Subtract 5.25 on both sides

3d=29.97

Divide both sides by 3

9.99 for each dozen of bagels

Hope this helps!


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The highest score of the women’s basketball championship was Jessica Bradley. She scored 147 more points and Tina Hardtner her t
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Answer:

MAKE MY ANSWER BRILLINEST PLEASE:)

Step-by-step explanation:

LET:

j = the points that Jessica scored

t = the points that Tina scored

Jessica scored 147 more points than Tina:

j = t + 1497

Together, Bradley and Harner scored 1601 points:

j + t = 1601

by solving the system of equations:

j = t + 147

j + t = 1601

we find

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Jessica Bradley scored 856 point.

Tina Harner scored 707 points.

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A box of coins contains nickels, dimes and quarters. The value of the coins is $4.00. If there were 3 times as many nickels, hal
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Read 2 more answers
Change the subject of the formula L = v 4kt - p to k.
Romashka [77]

Answer:

\boxed{k = \frac{L^2 + p}{4t}}

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

  1. Multiplication Property of Equality
  2. Division Property of Equality
  3. Addition Property of Equality
  4. Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle L = \sqrt{4kt - p}

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}

Next, <em>add p to both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}

Next, <em>divide 4t by both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}

We can rewrite the new equation by swapping sides to obtain our final expression:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}

∴ we have <em>changed</em> the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0
2 years ago
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