Three prime numbers which add up to 25

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

4 years ago

The secret number has a 7 in the ones place. The tens number is an odd number

Lana71 [14]

This really is left up to you as long as you have an odd number in the tens place and a 7 in the ones place. How big (or small) the number is is up to you. As long as it is at least 17, it's pretty much up to you.

7 0

3 years ago

The diagonal of a quadrilateral

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Quadrilateral is divided into two triangles

Triangle 1:

Diagonal = 16m , h = 12m

Area1 = $\frac{1}{2}base *height$

$=\frac{1}{2}*16*12\\\\=8*12\\\\= 96 m^{2}$

Triangle 2:

Area2 = $\frac{1}{2}*16*4$

= 8 * 4

= 32 square meter

Area of quadrilateral = 96 + 32 = 128 sq.m

8 0

3 years ago

Resolve into factors:- 9x4 + 2x²y²+ y4

makvit [3.9K]

Answer:

(3x^2+y^2+2xy)(3x^2+y^2-2xy)

Step-by-step explanation:

9x^4+2x^2y^2+y^4

(3x^2+y^2+2xy)(3x^2+y^2-2xy)

Both terms are perfect squares. So you will factor using the difference of squares formula. a^2-b^2=(a+b)(a-b)

Take what the square is for every term.

9x^4. What squared is 9? 3 and take half of the power or 2. That's how you get the 3x^2

2x^2y^2 is the same way. 2xy and 2xy

y^4 is y but dived he powers by 2 to get y^2.

Take one of each and but in () like I have above.

4 0

3 years ago

393 divided by 9 and remainder

malfutka [58]

Answer: 43.6 is the answer for your problem. If you have a question, just ask me.

5 0

4 years ago

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