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Tema [17]
3 years ago
8

Flowering plants with strong scents are usually pollinated by

Biology
1 answer:
Sidana [21]3 years ago
4 0
All flowers have different scents

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Which phrase describes a density-independent limiting factor that can affect
Alenkasestr [34]

The phrase dune erosion by ocean water along a shoreline best describes a density-independent limiting factor that can affect ecosystem stability (Option B).

<h3>What is a density-independent limiting factor?</h3>

A density-independent limiting factor can be defined as any factor in a given ecosystem that may alter the homeostasis of the population that lives in a given geographic area.

These factors (density-independent limiting factors) are generally abiotic factors such as hurricanes, extreme temperature conditions, the presence of contaminants in the air that hamper life in a given area, etc.

Conversely, density-dependent limiting factors are biotic factors such as competitive species that alter the development of another population.

Therefore, with this data, we can see that a density-independent limiting factor is any abiotic condition that may alter the life of a population in a give geographic area and thus alter the homeostasis of the whole ecosystem.

Learn more about density-independent limiting factors here:

brainly.com/question/20263955

#SPJ1

7 0
1 year ago
Read 2 more answers
In the late 1960s, Robert Paine conducted landmark studies on diversity in the rocky intertidal zone, comparing the species dive
Otrada [13]

Answer:

the questionnaire is incomplete, the options are attached to the graph

correct answer c

Paine's experiment was performed when exrtaer the starfish that was considered a negative predator by feeding on a local mussel, what was expected is that by eliminating the starfish it proliferates but its consequence was that it began to displace other species When the mussels became a predator due to the alteration of the ecosystem, the balance was removed and now the species cannot coexist.

4 0
3 years ago
What is the relationship between tm and %g=c for these samples? what might be the molecular basis of this relationship?
rodikova [14]
What are the answer choices
8 0
3 years ago
Suppose a species of bird called the red‑crested warbler has a plumage length that is controlled by a single gene. The P????mPlm
andreev551 [17]

Answer:

Check the explanation

Explanation:

North American:

112 birds total => 224 alleles

112 - 55 birds = 57 short plume birds.

q^2= (2*57) / 224 = 0.5089

Freq(short plume allele) = q = 0.7134

Freq(long plume allele) = p = 1 - q = 0.2866

From this North American population we get

0.2866 * 224 = 64 long plume alleles

0.7134 * 224 = 160 short plume alleles

South American:

452 birds total => 904 alleles

452 - 75 birds = 377 short plume birds.

q^2 = (2*377) / 904 = 0.8341

Freq(short plume allele) = q = 0.9133

Freq(long plume allele) = p = 1 - q = 0.0867

From this South American population we get

0.0867 * 904 = 78 long plume alleles

0.9133 * 904 = 826 short plume alleles

Blended population has

64 + 78 = 142 long plume alleles

160 + 826 = 986 short plume alleles

142 + 986 = 1128 total alleles

p = 142/1128 = 0.1259

q = 986/1128 = 0.8741

All right. The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.1259^2 + 2*0.1259*0.8741) = 236 birds

4 0
3 years ago
Although the proteins that cause the E. coli chromosome to coil are not histones, what property would you expect them to share w
oksano4ka [1.4K]

Answer:

Positively charged ions

Explanation:

Histones are a group of proteins with a N-terminal end of an amino acid, that binds to the DNA in the nucleus helping it to condense into Chromatin. DNA wraps around a core of proteins to initially form the NUCLEOSO ME structure, which is the basic subunit of Chromatin. Each nucleosome is made up of DNA coiled around two copies (2) of proteins- H2A, H2B, H3 and H4, to form a set of eight proteins called histone octamer.

Due to the phosphate group (PO4-) embedded in the DNA molecule, they assume a negative charge. The positively charged ions of the N(C) terminal end of histones which arise from the amino acid group they contain allows it to bind tightly to negatively charged DNA i.e. the more positively and negatively charged the histone and DNA are respectively, the tighter the binding.

Due to this property, the proteins that binds to DNA in E.coli, should possess a positive charge in similarity to histones in eukaryotes.

5 0
4 years ago
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