You would probably need a little larger sample of people because not all people wear corrective lenses. In almost any other survey, this would be a scientist’s dream, but in this one, you’d need it to be a little bigger.
A manufacturer<span> of </span>medical supplies produces 1 liter bags<span> of </span>saline solution. thecost<span> to </span>produce x thousand bags<span> of </span>saline<span> is </span>given<span> by the </span>cost<span> func. ... thousand </span>bags<span> of </span>saline<span> is</span>given<span> by the </span>cost function<span> C(x)=1.7x^2-5.3x+3.2, ...</span>
Answer:
There are 15 halves in 7 1/2.
Answer:
-9x+1 = -x +17
-8x = 16
x = -2
Step-by-step explanation:
Answer:
P(Y ≥ 15) = 0.763
Step-by-step explanation:
Given that:
Mean =135
standard deviation = 12
sample size n = 50
sample mean
= 140
Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses
Then,

The probability that X is greater than 140 is :
P(X>140) = 1 - P(X ≤ 140)



From z tables,


Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140
Then;


∴
P(Y ≥ 15) = 1- P(Y< 15)
P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y ≥ 15) = 0.763