Given:
.
To find:
The value of r.
Solution:
We have,
.
We know that the radius is perpendicular to the tangent at the point of tangency
AD is the tangent and CD is the radius. So, CD is perpendicular to AD at point D, i.e., .
Using Pythagoras theorem, we get
On further simplification, we get
Therefore, the value of r is 9.
Answer:
Part A
The rotation of the point (x, y) 180° about the origin gives the point (-x, -y)
Therefore, we have the points, ΔLMN, L(1, 1), and M(2, 2), and N(3, 3)
The coordinates of the vertices of the image, ΔL'M'N' are L'(-1, -1), and M'(-2, -2), and N'(-3, -3)
Please find attached the graph of triangle ΔLMN and ΔL'M'N'
Part B
The lines drawn through L and L' and through M and M' are colinear
Part C
A line is defined by two points, such as <em>L </em>and <em>M.</em> Rotation of a line through 180° about the origin will give an image location on the same path as the extension of the original line.
The third point, <em>N</em>, however, defines a plane, and the rotation of a plane by 180° will give an image which is turned upside down with regards to the preimage
Therefore, a trough in the preimage becomes a peak in the image and the lines drawn through N and N' crosses the colinear lines drawn throgh M and M' and L and L'
Step-by-step explanation:
