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Soloha48 [4]
3 years ago
5

What is the following product? ^3 square root 5 * square root 2

Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

The answer is B

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Factor completely: <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align="ab
Maurinko [17]
24  = 6 * 4
and 
6 + 4 = 10


so its the last choice.
6 0
3 years ago
Read 2 more answers
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0
3 years ago
Read 2 more answers
Simplify the expression 0.032 ÷ (8 × 10^-2)
Allisa [31]
\frac{0.032}{8\times10^{-2}} =  \frac{0.032}{0.08} = 0.4

Your answer is 0.4
3 0
2 years ago
You and your friend leave your houses at the same time to meet at a restaurant. The distance (in miles) your friend is from the
Katen [24]

Answer:

y = 80 -40x

Step-by-step explanation:

The given equation shows the friend arrives at the restaurant (y=0) when x=2. That is, half the initial distance to the restaurant is covered in each hour of travel time.

If I take 2 hours to travel the 80 miles from my house, my distance will decrease at the rate of 40 miles per hour. My distance from the restaurant can be represented by ...

... y = -40x +80

6 0
2 years ago
R t2. Simplify the expressionr stO D. r 15
leonid [27]
\frac{ r^{-3} s^{5} t^{2} }{ r^{2}s t^{-2} }= r^{-3-2} s^{5-1} t^{2-(-2)}= r^{-5} s^{4} t^{4}= \frac{s^{4} t^{4}}{ r^{5} }
Answer: option C.
6 0
2 years ago
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