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Rashid [163]
3 years ago
14

Penny reads 14 pages in 1/2 hour. What is the unit rate for pages per hour? For hours per page

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

28 pages an hour ggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg
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Solve system by elimination -9x - y =-19 <br> 5x + y = 15
vredina [299]

Answer:

(1, 10 )

Step-by-step explanation:

Given the 2 equations

- 9x - y = - 19 → (1)

5x + y = 15 → (2)

Adding the 2 equations term by term will eliminate the y- term

- 4x + 0 = - 4

- 4x = - 4 ( divide both sides by - 4 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for y

Substituting into (2)

5(1) + y = 15

5 + y = 15 ( subtract 5 from both sides )

y = 10

solution is (1, 10 )

6 0
2 years ago
Consider "Never Retreat" as a whole.
insens350 [35]

Answer: 3+3=9

⇔

Step-by-step explanation: three fingers to start add three fingers total of nine

4 0
2 years ago
Will give Branliest if you answer in the next five mins question is in the picture please hurry I'm about to get in trouble by m
Aleksandr-060686 [28]

Answer:

2.86

Step-by-step explanation:

Add all of them together to get 20, divide by the total employees so 7, you get 2.857. Round to nearest hundredth to get 2.86

4 0
3 years ago
Read 2 more answers
Im Triggered Pls Dont DELETE!
stepladder [879]

I'm assuming you mean f(x) = (e^x + 5x)^2, not f(x) = (e x + 5x)2, like your prompt suggests.


First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

\dfrac{d}{dx} [u^a] = a(u)^{a-1} du


Applying this, we can solve for the derivative:

f'(x) = 2(e^x + 5x) (e^x + 5)

  • Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.


Thus, our answer is:

f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}

7 0
3 years ago
Read 2 more answers
Eliminate the parameter. x = t^2 + 1, y = t^2 - 1.
Maksim231197 [3]

Answer:

Eliminating the parameter, the equation is y = x - 2

Step-by-step explanation:

We are given the following parametric equations:

x = t^2 + 1

y = t^2 - 1

We want to eliminate the parameter t. From the first equation:

x = t^2 + 1

t^2 = x - 1

Replacing in the second equation:

y = x - 1 - 1

y = x - 2

Eliminating the parameter, the equation is y = x - 2

7 0
3 years ago
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