The question is related to application of derivatives .
Let A represents the area and s represent the side length .
Differentiating both sides with respect to t
It is given that ds/dt = 4cm/s
Substituting the values of s, ds/dt and on multiplying them, we will get
dA/dt = 2(5)(4) = 40 cm^2/s
Therefore rate of change of area when area= and rate of change of side is 4 cm/s is 40
-3 ? i think if it’s wrong i’m sorry
Answer:
x = 8
Step-by-step explanation:
Taking the antilog, you have ...
3x +8 = 2^5 = 32
3x = 24 . . . . subtract 8
x = 8 . . . . . . .divide by 3
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You can have a graphing calculator show you the answer. Subtracting 5 from both sides gives ...
log2(3x +8) -5 = 0
The calculator can plot the left-side function and show you the value of x that makes it zero. That value is x=8.
Answer:
A= 19.625
Step-by-step explanation:
A= πr²
A= (3.14) 2.5^2
A= 19.625
Step-by-step explanation:
<u>Substitute the point (-9, 2) into the inequality:</u>
<u>Simplify:</u>
False.
-3 isn't greater than or equal to -2.
(-9, 2) is not a solution of