All categories

3 years ago

Find the area of the kite

Mathematics

2 answers:

wolverine [178]3 years ago

8 0

Answer: 10.5 sq. units

Step-by-step explanation:

Equation for kite: (p x q)/2

First, p = 3 and q = 7, so 3 x 7 = 21.

Next, 21 divided by 2 is our equation. Our answer for this equation would be 10.5.

Finally, add the correct unit measurement which would be “sq. units” in this case.

Hope this helps!

ki77a [65]3 years ago

3 0

Answer:

10.5 square units

Step-by-step explanation:

$A=\frac{pq}{2} =\frac{3*7}{2}=10.5m^2$

You might be interested in

7 1/6 times 3/4 is??

Paladinen [302]

Answer:

$7\frac{1}{8}$

Step-by-step explanation:

Multiply across.

$(7\frac{1}{6})(\frac{3}{4})=7\frac{3}{24}$

Then Simplify.

$7\frac{3}{24}=7\frac{1}{8}$

8 0

3 years ago

Convert 1/15 into a decimal correct to 2 decimal places

Citrus2011 [14]

Answer:

$\frac{1}{15} = 0.\overline{66}$

Step-by-step explanation:

We proceed to show the procedure to calculate the given fraction into a decimal form:

1) Since numerator is less than denominator, the integer component of the decimal number is zero:

$\frac{1}{15} = 0.xx$

2) We multiply the numerator by 10 and find the tenth digit:

$\frac{10}{15} = 0$

Then,

$\frac{1}{15} = 0.0xx$

3) We multiply the fraction in 2) by 10 and find the hundredth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.66x$

And the remainder is:

$r = 100-15\times 6$

$r = 10$

4) We multiply the remainder by 10 and divide this result by the denominator to determine the thousandth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.666$

This question asks us to write a decimal correct to 2 decimal places, which has the characteristic that is infinite periodical decimal. Then, the result correct to 2 decimal places is:

$\frac{1}{15} = 0.\overline{66}$

3 0

2 years ago

Mr. Cooper purchased a night stand

Vladimir [108]

Answer:

V = lwh

31050 = 36(28)w

31050 = 1008w

w = 31"

Step-by-step explanation:

This is ez lol

6 0

3 years ago

Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain

polet [3.4K]

First we will evaluate: ( substitution: u = x² - y², du = - 2 y dy )
$\int\limits^x_0 {y \sqrt{ x^{2} - y^{2} } } \, dy= \\ \frac{-1}{2} \int\limits^x_0 { u^{1/2} } \, du =$
= $\frac{-1}{3} \sqrt{ (x^{2} - y^{2} ) ^{3} }$ ( than plug in x and 0 )
= $- \frac{1}{3} ( \sqrt{( x^{2} - x^{2}) ^{3} } - \sqrt{ (x^{2} -0 ^{2} ) ^{3} }$ =
= 1/3 x³ ( then another integration )
$1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 ( x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )$
= 1/3 * 1/4 = 1/12

4 0

3 years ago

Solve for y where y(2)=2 and y'(2)=0 by representing y as a power series centered at x=a

Crank

I'll assume the ODE is actually

$y''+(x-2)y'+y=0$