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3 years ago

Find the area of the kite

Mathematics

2 answers:

wolverine [178]3 years ago

8 0

Answer: 10.5 sq. units

Step-by-step explanation:

Equation for kite: (p x q)/2

First, p = 3 and q = 7, so 3 x 7 = 21.

Next, 21 divided by 2 is our equation. Our answer for this equation would be 10.5.

Finally, add the correct unit measurement which would be “sq. units” in this case.

Hope this helps!

ki77a [65]3 years ago

3 0

Answer:

10.5 square units

Step-by-step explanation:

$A=\frac{pq}{2} =\frac{3*7}{2}=10.5m^2$

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3 years ago

Domain: Ranges: Zeros: Discontinuities: Asymptotes:

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3 years ago

An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

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Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

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Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$

= $15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}$

= 0.0154 + 0.00154 + 0.000064

= 0.01696

Therefore, probability of rolling at least 4 sixes is 0.01696.

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