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natulia [17]
3 years ago
5

Hey can you help we with this thanks

Computers and Technology
1 answer:
dimulka [17.4K]3 years ago
6 0
Hey, it's easy, come on!
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A married man gets a new job in a company. After three months, he meets a younger woman in the finance department and they begin
pav-90 [236]

Answer:

False ( B )

Explanation:

Of  the seven IT  infrastructure domains The USER domain was not at risk because the User Domain is not task with handling the sharing of data or Mutual communication between users in a Typical IT infrastructure.

The domain charged with such responsibility is The LAN domain because the LAN domain is charged with the sharing of information between the USERS and maintaining good mutual communication, and since the relationship has become sour, the sharing of information between the users will suffer the most and it will be at a high risk

5 0
3 years ago
Jenny wants to look at row 345 and compare it to row 17. What can she do if she wanted to easily adjust to see both at once?
S_A_V [24]

Assuming that Jenny is using MS Excel, the best way to look at both rows would be with the help of the "Freeze Panes" feature found in the View tab of the dashboard.

Jenny would simply have to select row 17 and click on "Freeze Panes". Once the panes are locked, Jenny will then have access to scroll down to row 345 with row 17 still showing its values.

8 0
4 years ago
Categorize each memory card as based on new or old technology. PLEASE HELP.
Leokris [45]

Answer:

SD Cards and XDQ Cards are new XD Cards and CF Cards are old.

Explanation:

Hope this helps.

4 0
3 years ago
Write a Common Lisp predicate function that tests for the structural equality of two given lists. Two lists are structurally equ
zysi [14]

Answer:

Explanation:

For the Program plan:

1. Two lists are structurally equal if they have the same list structure, although their atoms may be different.

2. So we are going to write a function that will check if elements in both lists at same position are atoms or not.

3. If yes then it should return true else false.

Program:

#lang scheme

( define (structurally-equal list1 list2)

(cond ((and (null? list1) (null? list2)) #t)

((or (null? list1) (null? list2)) #f)

((and (atom? (car list1)) (atom? (car list2)))

(structurally-equal (cdr list1) (cdr list2)))

((or (atom? (car list1)) (atom? (car list2))) #f)

(else (and (structurally-equal (car list1) (car list2))

(structurally-equal (cdr list1) (cdr list2) )))))

( define (atom? x) (not (or (pair? x) (null? x))))

6 0
3 years ago
An I/O-bound program is one that, if run alone, would spend more time waiting for I/O than using the processor. A processor-boun
Lelechka [254]

Answer with Explanation:

An I/O-bound the programs that are used relatively a little processor times and are favored by an algorithm. However, if the processor bound process is denied the processor time for the sufficiently long periods of times, the same algorithms will be granted a processor to the process and it has not use the processors at all in recent pasts. Therefore, the processor bound process will not be the permanently denied to access.

3 0
3 years ago
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