X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
A negative divided by a negative is a positive, so -14/-2 = 7
Hope this helped!
The answer to this question would be 8,4,4
Answer:
187.775
Step-by-step explanation:
20.3×9.25=
187.775
Answer:
The perimeter is 54 square units
Step-by-step explanation:
You find the sum of 12+12 and that's 24, and 15+15, and that is 30, and 30+24 is 54.
Hope this helped!