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Ymorist [56]
2 years ago
10

Tara's house is 50 feet long,her bike is 4 feet long,and Tara is 4 feet,9 inches .Combined,Tara,her house and her bike are still

10 feet shorter than the largest salami.How long was the largest salami?
Mathematics
2 answers:
tankabanditka [31]2 years ago
5 0

<u>Answer: </u>

The length of the largest salami is 48.75 feet

<u>Solution: </u>

Given,  

Tara’s house = 50 feet

Tara’s bike = 4 feet

Tara’s height = 4 feet 9 inches  

We know 12 inch = 1 foot

1 inch = \frac{1}{12} foot

9 inch = \frac{9}{12} foot = 0.75 foot

4 feet 9 inch = 4 feet +0.75 feet = 4.75 feet

Adding tara’s (house + bike + height) = 50+4+4.75 = 58.75

It is given that that combining tara’s house, bike and height  are 10 feet shorter than the largest salami which means difference between Tara’s(house + bike + height)  and largest salami  is 10.

Tara’s(house + bike + height) - largest salami   = 10

58.75 - largest salami = 10

58.75-10=largest salami

48.75 = largest salami.

The largest salami is 48.75 feet long

777dan777 [17]2 years ago
4 0

Answer:

68ft 9in.

Step-by-step explanation:

50 + 4+ 4 ft and 9 in. =58ft 9in.

58ft 9in. + 10ft = 68ft 9in.

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the length of a soccer pitch is 20 m less than twice its width. the area of the pitch is 6000m^2. find its dimensions.
Setler79 [48]
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:

x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60

x=60
2x-20=2(60)-20=120-20=100

Solution: the length is 100 m, and the width is 60 m.

To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.


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