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2 years ago

I'm so bad at math please anyone help :(

Mathematics

1 answer:

kondaur [170]2 years ago

6 0

It should be d. , Because if you take the equation 3x+y=9, and make it slope intercept form, it would be y= -3x+9. -3 is the slope, and 9 is the y intercept. D is the answer.

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What is 45% of 78? Plaese help or else idk i just needed to type more.

zepelin [54]

78×45/100
=35.1. As a result, 35.1 is 45% of 78. Hope it help!

3 0

3 years ago

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What is the value of 1/4m +n 8 - 6 = 12 *

yaroslaw [1]

Answer:

i dont know if you want me to solve for m

Step-by-step explanation:

Let's solve for m.

7 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

2 years ago

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I kinda need help on pentagram May someone please help me I don’t understand this.

Ad libitum [116K]

You just have to figure it where you can place 2 solid lines and get 10 triangles ( i can only get 9). Think about the pentagon in the middle of the triangles and see if somehow you can create more triangles using only the two straight lines.

6 0

2 years ago

HELP WITH THIS PLSSS ITS CYLINDERRR

Sindrei [870]

Answer:

6) B

7) D

Step-by-step explanation:

The surface area of a cylinder is 2 * pi * r * (r + h)

SA = 2 * 3.14 * 3.6 * (3.6 + 8.5) = 2 * 3.14 * 3.6 * 12.1 = 273.6 cm^2

The volume of a cylinder is pi * r^2 * h

V = 3.14 * (3.6)^2 * 8.5 = 345.9 cm^3

7 0

1 year ago

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