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dusya [7]
3 years ago
14

A large software company gives job applicants a test of programming ability and the mean for that test has been 160 in the past.

twenty-five job applicants are randomly selected from one large university and they produce a mean score and standard deviation of 183 and 12, respectively. use a 0.05 level of significance to test the claim that this sample comes from a population with a mean score greater than 160.

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
6 0
See attachment for answer.

grandymaker [24]3 years ago
3 0

Step-by-step explanation:

Mean of the test of programming ability was 160 in the past.

Again now, twenty-five job applicants are randomly selected from one university and they produce a mean score and standard deviation of 183 and 12.

So in this case, the null hypothesis will be,

H_o: \mu = 160

and alternate hypothesis will be,

H_a: \mu > 160

Mean of the sample = \overline{x} = 183

Standard deviation of the sample = \sigma = 12

sample size = n = 25

Using t distribution,

t=\dfrac{\overline{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

=\dfrac{183-160}{\frac{12}{\sqrt{25}}}

=9.58

P-value =P(t > 9.58)\approx 0

As the obtained value is less than 0.05 or 5% level of significance, so we have to reject the null hypothesis.

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Aliun [14]
Hello!

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Add

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5 0
3 years ago
Read 2 more answers
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strojnjashka [21]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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PIT_PIT [208]

Answer:

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Step-by-step explanation:

Given the data points :

66, 8) (71, 23) (72 16) (75 30) (78 35) (80 24) (82 37) (86 37) (87 42) (90 50)

Temperature X:

66

71

72

75

78

80

82

86

87

90

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23

16

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35

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37

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Using the online regression calculator :

The regression model obtained is ;

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Where

1.5045 = gradient or slope

-88.2056 = intercept

x = independent variable

y = dependent variable

Number of swimmers when temperature = 88

y = 1.5045(88) - 88.2056

y = 44.19

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weqwewe [10]
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kvv77 [185]

Answer:

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Step-by-step explanation:

i think its correct

6 0
3 years ago
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