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dusya [7]
3 years ago
14

A large software company gives job applicants a test of programming ability and the mean for that test has been 160 in the past.

twenty-five job applicants are randomly selected from one large university and they produce a mean score and standard deviation of 183 and 12, respectively. use a 0.05 level of significance to test the claim that this sample comes from a population with a mean score greater than 160.

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
6 0
See attachment for answer.

grandymaker [24]3 years ago
3 0

Step-by-step explanation:

Mean of the test of programming ability was 160 in the past.

Again now, twenty-five job applicants are randomly selected from one university and they produce a mean score and standard deviation of 183 and 12.

So in this case, the null hypothesis will be,

H_o: \mu = 160

and alternate hypothesis will be,

H_a: \mu > 160

Mean of the sample = \overline{x} = 183

Standard deviation of the sample = \sigma = 12

sample size = n = 25

Using t distribution,

t=\dfrac{\overline{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

=\dfrac{183-160}{\frac{12}{\sqrt{25}}}

=9.58

P-value =P(t > 9.58)\approx 0

As the obtained value is less than 0.05 or 5% level of significance, so we have to reject the null hypothesis.

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Sergio039 [100]

Answer:

E=x

or 110= x ( opposite angles of parallelogram are congurent)

E+D = 180 ( angles on st line)

110+D =180

D=70

D=F ( opposite angles of parallelogram are congurent)

so F=70

3 0
3 years ago
For a sale, a store decreases its prices on all items 20%. An item that cost $120 before the sale now costs $120 - 0.2($120). Wh
tino4ka555 [31]
If the store decreases its prices by 20%, then ur actually paying 80%

0.80(120)  <=== ur expression

lets check..
0.80(120) = 96
120 - 0.2(120) = 120 - 24 = 96 (yep, it matches)
4 0
3 years ago
Help with number 8 plz and tell me how you did it!
yulyashka [42]
Well, there are 0.25 quarts in a cup so if Krystal makes 18 cups of soup, she can serve 72 guests! because,
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7 0
3 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

8 0
3 years ago
Please HELP me 50 points worth
Leokris [45]

Answer:

y=-½x + 1

Step-by-step explanation:

1.) a perpendicular lines uses the opposite inverse of a line so the slope becomes -½x

2.) make an equation that looks as so:

y=-½x+b

the y intercept is unknown so it must be a variable.

3.) substitute the points you are given into the equation:

3=-½(4)+b

4.) solve for b

3=2+b

-2|-2

1=b

4.) place b into the equation

y=-½x + 1

8 0
3 years ago
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