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svetoff [14.1K]
4 years ago
9

Prepare 1500 ml of 5.0 M H2SO4 from a stock H2SO4 which is 80% pure and a s.g of 1.018

Mathematics
1 answer:
pentagon [3]4 years ago
3 0

To solve this we use the equation,

 

<span> M1V1 = M2V2</span>

 

<span> where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.</span>

<span>
</span>

<span>M1 = .80 g H2SO4 / g solution (1018 g solution / L solution ) (1 mol / 98.08) = 8.30 M</span>

<span>
</span>

<span>8.30 (V1) = (5.0 M) (1.5 L)</span>

<span>V1 = 0.9036 L or 903.6 mL of the stock needed</span>

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