Find the value of x. Round to nearest tenth. A. 24.2 B. 17.0 C. 20.1 D. 16.0

Determine if the following statement is true or false.

Alla [95]

Answer:

A. True

Step-by-step explanation:

The general formula for predicting an outcome in a binomial probability distribution function is: nCx(p)^x(q)^(n-x)

where p is the probability of success and q is the probability of failure

From the above formula; nCx represent the number of ways of obtaining x successes in n trials.

nCx is a combination computation and combination helps to determine in how many ways a certain outcome is possible.

3 0

4 years ago

A hemisphere has a diameter of 10 inches. what is the surface area of the hemisphere

NeX [460]

Step-by-step explanation:

surface area of hemisphere=2πr²

2×22/7×5×5
157.14in²

<h3>stay safe healthy and happy ..</h3>

7 0

3 years ago

Which function has no x intercepts?

Svetach [21]

why you dont searched un gogle :v

4 0

3 years ago

Read 2 more answers

PLZZZZ HELP MEEEE

Yuki888 [10]

X=3
r≥8
n=6
Plug the answers in until you get on that fits the best.

3 0

3 years ago

Read 2 more answers

Find a decomposition of a=⟨−5,−1,1⟩ into a vector c parallel to b=⟨−6,0,6⟩ and a vector d perpendicular to b such that c+d=a.

dezoksy [38]

The projection of vector A parallel to vector B is $\langle -3, 0, 3\rangle$ and the projection of vector A perpendicular to vector B is $\langle -2, -1, -2\rangle$ .

In this question, we need to determine all projections of a vector with respect to another vector. In this case, the projection of vector A parallel to vector B is defined by this formula:

$\vec a_{\parallel , \vec b} = \frac{\vec a \,\bullet\,\vec b}{\|\vec b\|^{2}}\cdot \vec b$ (1)

Where $\|\vec b\|$ is the norm of vector B.

And the projection of vector A perpendicular to vector B is:

$\vec a_{\perp, \vec b} = \vec a - \vec a_{\parallel, \vec b}$ (2)

If we know that $a = \langle -5, -1, 1 \rangle$ and $\vec b = \langle -6, 0, 6 \rangle$ , then the projections are now calculated:

$\vec a_{\parallel, \vec b} = \frac{(-5)\cdot (-6)+(-1)\cdot (0)+(1)\cdot (6)}{(-6)^{2}+0^{2}+6^{2}} \cdot \langle -6, 0, 6 \rangle$

$\vec a_{\parallel, \vec b} = \frac{1}{2}\cdot \langle -6, 0, 6 \rangle$

$\vec a_{\parallel, \vec b} = \langle -3, 0, 3\rangle$

$\vec a_{\perp, \vec b} = \langle -5, -1, 1 \rangle - \langle -3, 0, 3 \rangle$

$\vec a_{\perp, \vec b} = \langle -2, -1, -2\rangle$

The projection of vector A parallel to vector B is $\langle -3, 0, 3\rangle$ and the projection of vector A perpendicular to vector B is $\langle -2, -1, -2\rangle$ .

We kindly invite to check this question on projection of vectors: brainly.com/question/24160729

7 0

3 years ago