Answer:
1.-t₁  =  0,625 s
2.-h(max)  =  6,25 f
3.-t = 1,25 s
Step-by-step explanation:
V₀  =  20 f/s
h(t)  =  - 16*t² + 20*t
h(max)  =  ??
h´(t)  = - 32*t + 20
h(max) will occurs when  V = 0   dh/dt  = 0  then
- 32*t  + 20  = 0
- 32*t  =  -20
t  =  20/32
t₁  =  0,625 s
h(max) = h(0,625)    =  - 16*(0,625)² + 20*0,625
h(max)  =  - 6,25  +  12,5
h(max)  =  6,25 f
c) The ball will hit the ground 
t = 2*t₁
t  = 2*0,625
t = 1,25 s
 
        
             
        
        
        
Answer:
4:35 am
Step-by-step explanation:
change 04:35 to 12 hours clock time
 
        
             
        
        
        
The first step is to change the mixed number into an improper fraction.
1 7/10 = 17/10
(17/10) / (3/5) = 
(17/10) * (5/3) = (change the division to a multiplication by the reciprocal.
17/6 = 2 5/6
        
                    
             
        
        
        
6 balls in the bag 
1/6 getting the random color 
1/6=about .16
so C
        
             
        
        
        
X=4 x=-4 Due to the difference in squares theorem