Answer:
1.-t₁ = 0,625 s
2.-h(max) = 6,25 f
3.-t = 1,25 s
Step-by-step explanation:
V₀ = 20 f/s
h(t) = - 16*t² + 20*t
h(max) = ??
h´(t) = - 32*t + 20
h(max) will occurs when V = 0 dh/dt = 0 then
- 32*t + 20 = 0
- 32*t = -20
t = 20/32
t₁ = 0,625 s
h(max) = h(0,625) = - 16*(0,625)² + 20*0,625
h(max) = - 6,25 + 12,5
h(max) = 6,25 f
c) The ball will hit the ground
t = 2*t₁
t = 2*0,625
t = 1,25 s
Answer:
4:35 am
Step-by-step explanation:
change 04:35 to 12 hours clock time
The first step is to change the mixed number into an improper fraction.
1 7/10 = 17/10
(17/10) / (3/5) =
(17/10) * (5/3) = (change the division to a multiplication by the reciprocal.
17/6 = 2 5/6
6 balls in the bag
1/6 getting the random color
1/6=about .16
so C
X=4 x=-4 Due to the difference in squares theorem
