Answer:
BA = 25π,
LA = 25√2π,
TA = 25π + 25√2π,
V = 41 and 2 / 3π
Step-by-step explanation:
We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,
( Height = 5 inches = Radius
______
Now knowing the height, let's begin by calculating the base area. By it's name, we have to find the area of the base. As it is a circle, let us apply the formula " πr^2 "
- Base Area = 25π
______
The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula,
-
- Lateral Area = 25√2π
______
And the surface area is the base area + lateral area -
- Surface Area
______
The volume of a cone is 1 / 3rd that of a cylinder, with a simple formula of Base * height. Therefore, we can conclude the following -
- Volume = 41 and 2 / 3π
Answer:
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18%</u></h2>
Step-by-step explanation:
To do this, we first divide 2.87 by 3.50. This gets us 0.82. So we now know that 2.87 is 82% of 3.50. But we're trying to find the reduced amount. So we now Do 100%-82% (82% being 2.87) to get 18%. So the answer is 18%. To make sure we are right, we do 18% of 3.50 to get 0.63 cents. We then take 3.50 and subtract 0.63 to get 2.87. So it reduced by 18%
The formula for Y-intercept is y=mx+b.
b is your y-intercept so in your case the line would go through -4 on the y axis.
m is your slope and your slope is rise over run or y over x. In the equation your slope is 5/1 so 5 up and 1 right. After doing that you get your line after adding another point on the graph.
The process of combustion involves reacting fuel with a
given oxidant (most of the time oxygen from the atmosphere). Complete
combustion is a type of combustion that produces carbon dioxide and water. An
example of this is 2C2H6 + 7O2 = 4CO2 + 6H2O.