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3 years ago

Joey Chestnut can eat 3 hotdogs in 25 seconds. How many can he eat in a minute? How many can he eat in 10 minutes?

1 answer:

3 0

First divide 60 by 25.
60/25 = 2.4
Then multiple 2.4 and 3 to find how many hotdogs Joey can eat in a minute (60 seconds).
2.4*3 = 7.2
The answer must be rounded down as he hasn't completed his 8th hotdog yet, so Joey can eat 7 full hotdogs in a minute.
To find how many he can eat in 10 minutes, multiply 7.2 by 10.
10*7.2 = 72
Therefore, Joey can eat 72 hotdogs in 10 minutes.

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9x-2y=-21 2x+3y=16 Substitution

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3 years ago

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3 years ago

Read 2 more answers

A bag contains Red, Green and Yellow balls. A ball is taken at random from the bag. The probability that it is Red is 0.35 and t

Eddi Din [679]

Answer:

P(Yellow)=0.25
P(Not Red)=0.65

Step-by-step explanation:

P(Red)=0.35

P(Green)=0.4

(a)Since there are three colours inside the bag

P(Red)+P(Green)+P(Yellow)=1

0.35+0.4+P(Yellow)=1

P(Yellow)=1-(0.35+0.4)

P(Yellow)=0.25

(b) In probability, the sum of an event and its complement is 1.

Therefore:

P(Red)+P(Not Red)=1

0.35+P(Not Red)=1

P(Not Red)=1-0.35

P(Not Red)=0.65

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3 years ago

At a restaurant, 25% of the dinner plates are clean. There are 80 total dinner

pochemuha

Answer:

Step-by-step explanation:

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3 years ago

8) through: (-3, -2), perp. to y = x – 1 A) y=-5x – 1 B) y=-4x – 5 C) y=-x – 5 D) y=-5x – 4

nexus9112 [7]

Answer:

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

Solution:

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1$

We know that, product of slopes of perpendicular lines is -1.

So, 1 $\times$ slope of perpendicular line = -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

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3 years ago