Answer:
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The dimension of the box is 50in by 10in by 15in
<h3>How to calculate the volume of a figure</h3>
The volume of an object is the quantity of substance it contains.
The formula for calculating the volume of the box is expressed as:
V = lwh
where:
- l is the length
- w is the width
- h is the height
Given the following parameters
length = 5w
height = w + 5
Substiute
7500 = 5w(w)(w+5)
7500 = 5w²(w+5)
1500 = w³+5w²
w³+5w² - 1500 = 0
<u>Factorize to determine the width</u>
On factorizing, the width of the box is 10 inches
Recall that:
l = 5w
l = 5(10)
l = 50inches
<u>Get the height</u>
h = w + 5
h = 10 + 5
h = 15inches
Hence the dimension of the box is 50in by 10in by 15in
Learn more on volume of box here: brainly.com/question/14957364
Step-by-step explanation:
<h2>—Math</h2>
x² – 2x + 7 = 4x – 10
x² –2x – 4x + 7 + 10= 0
x² –6x + 17 = 0
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C
Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)
By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)
Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.
Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
