Answer:
5.2 I am guessing.
Step-by-step explanation:
Answer:
1) The square ABCD was dilated to form square A'B'C'D' using a scale factor of 1/2
2) The pair of polygons is not similar because their corresponding sides are not proportionals.
Step-by-step explanation:
1) Scale factor: f=?
f=Final dimension / Initial dimension
f=A'B'/AB=B'C'/BC=C'D'/CD=A'D'/AD
f=2/4
Simplifying the fraction dividing the numerator and denominator by 2:
f= (2/2) / (4/2)
f=1/2
2) Let's check the proportion between their corresponding sides:
AM/A'M'=(11 ft)/(9.4 ft)=1.17
HT/H'T'=(11 ft)/(9.4 ft)=1.17
HM/H'M'=(10 ft)/(8.4 ft)=1.19
AT/A'T'=(10 ft)/(8.4 ft)=1.19
AM/A'M'=HT/H'T'=1.17 but different to 1.19=HM/H'M'=AT/A'T'
Then, the pair of polygons is not similar
Hey! (2x + 8)(4x + 7) = 2x(4x + 7) + 8(4x + 7) = 8x^2 + 14x + 32x + 56 =
8x^2 + 46x + 56 <==
Hope this helps! :)
Answer:
128 my answer needs to be long so im just gonna span a little
435 being the constant means that is what they started with
Hope this helps :)
