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vovangra [49]
3 years ago
11

5. Find wº in the acute triangle. 63° 490

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

68

Step-by-step explanation:

180 - 63 - 49 = 68

kotykmax [81]3 years ago
4 0
68 would be the answer
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Step-by-step explanation:

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49–2ax –a^2–x^2 factor
vampirchik [111]

49–2ax –a^2–x^2

Extract the negative sign

= 49 - (a^2 +2ax +x^2)

Factor using a^2 + 2ab + b^2 = (a+b)^2

= 49 - (a+x)^2

Factor using a^2 - b^2 = (a-b)(a+b)

= ( 7- (a + x)) * (7 + (a + x))

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2 years ago
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
2 years ago
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