Answer:
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Step-by-step explanation:
This system of inequalities has a shared portion at the origin, so we can easily jump to using the zero-interval test [test point (0, 0)] to verify the inequalities as false or true:
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Plus, the top inequality has a <em>dashed </em><em>line</em><em> </em>["<" or ">"], and the bottom inequality has a solid line, so this must have an equivalence line underneath each inequality symbol ["≤" or "≥"].
** Hold on though! Although it looks obvious about what the second inequality is, we need to double-check and make sure anyway, just to be on the safe side ☺:

From the y-intercept of
we do
by either moving four blocks <em>north</em><em> </em>over five blocks <em>west</em><em> </em>or four blocks <em>south</em><em> </em>over five blocks <em>east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. This IS what our solid graph looks like, so we are correct!
So, from all what was explained, you have your answer.
I am joyous to assist you anytime.
The answer is C. 16 since the 3 first surveys medians are 15,16,16. The median of those 3 numbers is 16. So the answer would be C. 16
It’s A I had this question before
<span>SAS
You've been given that AC = BC. So that's the first side or S of the proof. Then you've been given â 3 = â 4, which is the angle. And finally, CM = CM, which is the second S. So you have AC=BC, and â 3 = â 4, and finally CM = CM. So SAS can be used to prove that triangle ACM is congruent to triangle BCM.</span>