Differentiate y= xe^x+7

If a monopolist supplies goods at a price; P = 170 - Q, with marginal cost; MC = 52. Find the quantity and price

Arada [10]

Answer:

Quantity = 59 units

Price = $111

Step-by-step explanation:

The Demand function is given by

$P = 170 - Q$

The Marginal cost is given by

$MC = 52$

We are asked to find the quantity and price of goods.

Firstly, obtain the Marginal revenue function from the demand function

The Total revenue is given by

$TR = P \times Q \\\\TR = (170 - Q) \times Q \\\\TR = 170Q - Q^2$

The Marginal revenue is the derivative of the Total revenue,

$MR = \frac{d}{dQ} (TR) = 170Q - Q^2 \\\\MR = \frac{d}{dQ} (TR) = 170 - 2Q \\\\$

Assuming that the monopolist maximizes profits,

$MR = MC \\\\170 - 2Q = 52\\\\2Q = 170 - 52\\\\2Q = 118\\\\Q = 118/2\\\\Q = 59$

Therefore, the quantity is 59 units.

The price of each good is

$P = 170 - Q \\\\P = 170 - 59 \\\\P = 111$

Therefore, the price is $111.

3 0

4 years ago

Please i need your help

bonufazy [111]

Answer:

Can you take a full picture

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Referring to triangle ABC, find the area of the triangle.

ExtremeBDS [4]

Answer: area of triangle = 13.4 ft ( after rounding the answer to 3 significance figures)

Step-by-step explanation:

formula for the area of triangle

= S + S + S

= 4.34 + 3.78 + 5.27

= 13.9 ft

= 13.4 ( after rounding off to three significant figures )

5 0

4 years ago

The sum of 8th term of an A.P is 160 while to sum of the 20th term is 880. Find the 43rd term

marshall27 [118]

Let a and d be the first term and common difference, respectively. Then

the 8th term is a+7d
the 20th term is a+19d

The sum of the first 8 terms is
(a)+(a+d)+(a+2d)+...+(a+7d) = 8a+28d

The sum of the first 20 terms is
(a)+(a+d)+(a+2d)+...+(a+19d) = 20a+190d

So

8a + 28d = 160
20a+ 190d = 880

40a + 140d = 800
40a + 380d = 1760
240d = 960
d = 4

8a + 112 = 160
8a=48
a =
6

The first term is 6 and the common difference is 4.

The 43rd term is a+42d = 6+42(4) = 6+168 = 174

The sum of the first 12 terms is
(a)+(a+d)+(a+2d)+...+(a+11d) = 12a+66d = 12(6)+66(4) = 72+264 = 336

8 0

3 years ago

Balu had a collection of coins. 1/2 of the coins are from asian countries, 1/3 of them from european countries, 36 are from amer

Georgia [21]

The total number of coins Balu had in his collection was 216 coins, computed using the linear equation in one variable, x = x/2 + x/3 + 36.

Asian coins were 1/2 a fraction of this, that is, (1/2)*216 = 108 coins.

We assume the total coins with Balu to be x.

The fraction of coins from Asian countries = 1/2.

Thus, the number of coins from the Asian countries = 1/2 of x = x/2.

The fraction of coins from European countries = 1/3.

Thus, the number of coins from the European countries = 1/3 of x = x/3.

The number of coins from America = 36.

Thus, the total number of coins = x/2 + x/3 + 36.

But, we assumed that the total number of coins is x.

Thus, we get a linear equation in one variable as follows:

x = x/2 + x/3 + 36.

We solve this equation as follows:

x = x/2 + x/3 + 36,

or, x - x/2 - x/3 = 36,

or, (6x - 3x - 2x)/6 = 36,

or, x/6 = 36,

or, x = 36*6 = 216.

Thus, the total number of coins Balu had in his collection was 216 coins, computed using the linear equation in one variable, x = x/2 + x/3 + 36.

Asian coins were 1/2 a fraction of this, that is, (1/2)*216 = 108 coins.

Learn more about fractions at

brainly.com/question/2929160

#SPJ4

3 0

2 years ago