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3 years ago

8

Dana has n quarters. Ivan has 2 fewer than 3 times the number of quarters Dana has. The expression n + 3 n−2 gives the number of

quarters they have altogether. Which is another way to write this expression?

1 answer:

Nesterboy [21]3 years ago

3 0

You can "collect terms" and write it as
4n -2

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What's the answer ??????

maw [93]

Table D is the correct answer because there are no repeating numbers in the input.

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3 years ago

Find the area of the shaded region. Round to the nearest tenth if necessary.

Ratling [72]

The answer I got is 155.5. First I broke this into a rectangle ad a trapezoid. The rectangles area is 15x5 = 75. The area of the trapezoid is 1/2(8+15)7 = 23x3.5 = 80.5. So 80.5 + 75 = 155.5

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3 years ago

A jar of 50 sour ball candies contains only 3 flavors. If there are 18 orange, 12 lemon, and 20 cherry sour balls, what is the p

Alla [95]

Option B. 12/ 125 is the answer.

Explanation

Total umber of sour ball candies = 50

Number of lemon candies = 12

Hence the probability to get a lemon candy is = 12/50

Number of cherry sour balls = 20

So, the probability to get a cherry sour ball = 20/50

So, to get the joint probability for a random selection to either get a lemon or cherry candy, we will multiply both the probabilities.

$\frac{12}{50}*\frac{20}{50}$

= $\frac{12}{125}$

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3 years ago

How much scissors weigh in grams

Ne4ueva [31]

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4 0

4 years ago

Read 2 more answers

Without solving, determine the number of real solutions for each quadratic equation.

masha68 [24]

Answer:

1. x^2 − 4x + 3 = 0

$b^2 -4ac = (-4)^2 -4(1)*(3)= 4 >0$ So we have two real solutions

2. 2n^2 + 7 = −4n + 5

$b^2 -4ac = (4)^2 -4(2)*(2)= 0$ So we just one real solution

3. x − 3x^2 = 5 + 2x − x^2

$b^2 -4ac = (1)^2 -4(2)*(5)= -19$ No real solutions

4. 4x + 7 = x^2 − 5x + 1

$b^2 -4ac = (-9)^2 -4(1)*(-6)= 105 >0$ So we have two real solutions

Step-by-step explanation:

1. x^2 − 4x + 3 = 0

We need to compare this function with the general equation for a quadratic formula given by:

$f(x) = ax^2 + bx + c$

On this case we see that a=1, b = -4 and c =3

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (-4)^2 -4(1)*(3)= 4 >0$ So we have two real solutions

2. 2n^2 + 7 = −4n + 5

We can rewrite the expression like this:

$2n^2 +4n +2$

On this case we see that a=2, b = 4 and c =2

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (4)^2 -4(2)*(2)= 0$ So we just one real solution

3. x − 3x^2 = 5 + 2x − x^2

We can rewrite the expression like this:

$2x^2 +x +5$

On this case we see that a=2, b = 1 and c =5

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (1)^2 -4(2)*(5)= -19$ No real solutions

4. 4x + 7 = x^2 − 5x + 1

We can rewrite the expression like this:

$x^2 -9x -6$

On this case we see that a=1, b = -9 and c =-6

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (-9)^2 -4(1)*(-6)= 105 >0$ So we have two real solutions

8 0

4 years ago