Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .
Rule: (x, y)→(x + 8, y + 1 )
J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)
J’ (6,3)
K’ (5,-3)
L’ (9,-1)
Hope this helps!
Hi there
The formula is
A=pe^rt
We need to solve for p where
A future value 15000
P present value?
E constant
R interest rate 0.059
T time 12 years
So when you solve for p you get
P=A÷e^rt
P=15,000÷e^(0.059×12)
P=7,389.43
Hope it helps
Me just so I can ask a question
Answer:
x=2 or x=3
Step-by-step explanation:
x^4 - 5x^3 + 7x^2 - 5x + 6 = 0
Step 1=Factor left side of equation.
(x-2) (x-3) (x^2 + 1) = 0
Step 2=Set factors equal to 0.
x-2 = 0 or x-3 = 0 or x^2 + 1 = 0.
Answer:x=2 or x=3