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Brilliant_brown [7]
3 years ago
14

PLEASE!!!I NEED HELP!!!!!!!

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
What is the simplified expression for: (Picture Down Below)
B. 3^2/2^2
\frac{3^-4*2^3*3^2}{2^4*3^-3}
Hope this helps!
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Determine if (-2,5) is a solution of Of 3x+4y=14
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Well that's easy. Just plug in the numbers: 3*(-2)+4*(5)=14. So yes the solution is correct.
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in the figure above, bc and ad are parallel, ab and ec are parallel, cd=ce, and the measure of angle abc is 115 degrees. what is
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"in the figure above" ?

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129 is 43% of what amount?
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129/43x100=300
129 is 43% of 300
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The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in amb
Zigmanuir [339]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

114, 261, 319, 183,654,313,58,98,335,324,52,125,342,66,321,893,690,798,201,74,632,216,76,155,161,304,530,1110,93,631,75,344,264,1120,122,45,304,192,316,63

USING CALCULATOR :

The mean(m) of the data: = ΣX/n

n = sample size = 40

m = 12974/40

m = 324.4

Median = ((n + 1)/2) th term = 41/2 = (20 + 21)th term / 2

= (261 + 264) / 2 = 262.5

Standard deviation (s) = sqrt(Σ(x - m)²/n))

s = 281. 74

B.) Coefficient of skewness (Ks) :

3(mean - median) / standard deviation

3(324.4 - 262.5) / 281.74

= 0.66

Mild positive skewness Given a positive skew Coefficient value.

(d-1) Are there any outliers?

Yes

Four outliers

(d-2) What are the limits for outliers? (Round your answers to 1 decimal place. Negative amounts should be indicated by a minus sign.)

Lower bound = Q1 - (1.5 * IQR)

Upper bound = Q3 + (1.5 * IQR)

IQR = Q3 - Q1

Q3 = upper quartile = 343 ; Q1 = 106 ; Q2 = 262.5

IQR = 343 - 106 = 237

Lower bound = 106 - (1.5 * 237) = - 249.5

Upper bound = 343 + (1.5 * 237) = 698.5

-249.5 ≤ X ≤ 698.5

4 0
3 years ago
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