What is the value of x? 6.75+3/8x=13 1/4

Which is the completely factored form of 12x3 – 60x2 4x – 20? 4(3x2 – 1)(x – 5) 4x(3x2 1)(x – 5) 4x(3x2 – 1)(x 5) 4(3x2 1)(x – 5

Neporo4naja [7]

The factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

<h3>Factorization;</h3>

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; $\rm 12x^3 - 60x^2 + 4x -20$

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

$\rm 12x^3 - 60x^2 + 4x -20\\\\ 12x^3(x-5)+4(x-5)\\\\(12x^3+4)(x-5)\\\\ 4(3x^2 + 1)(x-5)$

Hence, the factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

To know more about factorization click the link given below.

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4 0

2 years ago

Please answer and use statement reason

masha68 [24]

Answer:

x = 15

Step-by-step explanation:

FD and AC are parallel because both are perpendicular to EB. Angle EDF and Angle DCA are congruent because they are corresponding angles. The measure of Angle DCA is also 3x because congruent angles have the same measure.

Now consider Triangle ACD. Because the sum of all three measures of the angles in a triangle add up to 180°.

x + 8x + 3x = 180°

12x = 180°

12x/12 = 180/12

x = 15

8 0

2 years ago

In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point

Masja [62]

The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

<h3>How to calculate the electric field?</h3>

Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,

The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k

Since V = 2x − 5x²y + 3yz²

dV/dx = d(2x − 5x²y + 3yz²)/dx

= d2x/dx - d5x²y/dx + d3yz²/dx

= 2 - 10xy + 0

= 2 - 10xy

dV/dy = d(2x − 5x²y + 3yz²)/dy

= d2x/dy - d5x²y/dy + d3yz²/dy

= 0 - 5x² + 3z²

= - 5x² + 3z²

dV/dz = d(2x − 5x²y + 3yz²)/dz

= d2x/dz - d5x²y/dz + d3yz²/dz

= 0 - 0 + 6z

= 6z

<h3>The electric field</h3>

So, E = -grad(V)

= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]

= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

So, the electric field at (-2, 2, 0) is

E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]

E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]

E = -[42i + (-20 + 0)j + (0)k]

E = -[42i - 20j + 0k]

E = -42i + 20j - 0k

<h3>The magnitude of the electric field</h3>

So, the magnitude of E at (-2, 2, 0) is

|E| = √[(-42)² + 20² + 0²]

= √[1764 + 400 + 0]

= √2164

= 46.52 V/m

So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

Learn more about electric field here:

brainly.com/question/25751825

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3 0

2 years ago

Find the area of the triangle (but identify which formula to use). Please help!

GalinKa [24]

A.) A= (1/2)absinC
b.) sinA/a, sinB/b, sinC/c
sin100/42, sin25/b, sinC/c
use these two fractions.
sin100/42= sin25/b
cross multiply next
b×sin100= 42×sin25
then divide on both sides by sin100
b=18
c.)measurementofA+measurementofB+measurementofC=180
100+25+C=180
125+C=180
-125 -125
The measurement of angle C is 55 degrees.
d.)A=(1/2)42×18×sin55
= 21×18×sin55
A =309.6 units squared

7 0

3 years ago

the graph shows the speed of a vehicle during the final 50 seconds of a journey at the start of the 50 seconds the speed is k me

Simora [160]

Answer:

a) 27 m/s

b) 30 m/s

c) i) 3

ii) Deceleration

Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey. At the start of the 50 seconds the speed is k metres per second. The distance travelled during the 50 seconds is 1.35 kilometres.

(a) Work out the average speed of the vehicle during the 50 seconds

(b) Work out the value of k.

(c) (i) Calculate the gradient of the graph in the final 10 seconds of the journey

(ii) Describe what this gradient represents

Answer:

The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

$Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s$

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

$Total \ distance=Total\ area=Area\ of \ rectangle+Area\ of \ triangle\\Total \ distance=(length *breadth)+\frac{1}{2}base*height\\1350 \ m=(40*k)+0.5*10*k\\1350=40k+5k\\45k=1350\\k=1350/45\\k=30\ m/s$ c) i) The gradient in the last 10 seconds is the ratio of change in speed to change in time

$Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40} \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3$

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

6 0

3 years ago