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professor190 [17]
4 years ago
10

Which fractions are equivalent to 40%

Mathematics
1 answer:
rusak2 [61]4 years ago
6 0
The awnser will be 2/5 or 1/4
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A person jogs 1/4 mile in 1/16 hour. The person's speed is ______ miles per hour.
Gemiola [76]
It would be 4 miles an hour because just adding one of its self untill the 1/16 is whole would be that 1/4 has made 4 of its self already
8 0
4 years ago
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BOOKS The owner of a bookstore
mina [271]
10% = 50
30% = 150
1% = 0.5
2% = 1
150 + 1 = 151 books should be mysteries
5 0
3 years ago
Find the zero of each function and state the multiplicity of each zero. Please show all steps.
vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.


Step-by-step explanation:

1. y=(x+3)^3

y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3

Zero: x=-3 multiplicity 3.


2. y=(x-2)^2 (x-1)

y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.

Zeros: x=2 multiplicity 2; x=1 multiplicity 1


3. y=(2x+3)(x-1)^2

y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.

Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

4 0
3 years ago
Mary deposits $400 into an account that pays simple interest at a rate of 2% per year. How much interest will she be paid in the
yawa3891 [41]

Answer:

$16

Step-by-step explanation:

Simple interest is based on the principal amount of a loan or deposit, whereas compound interest is based on the principal amount and the interest that accumulates on it in every period.

Simple Interest = P x r x n

where P = Principal amount, r = Annual interest rate, n = Term of loan, in years​

2% = 2 ÷ 100 = 0.02  so r = 0.02

Therefore,  

Simple Interest = 400 x 0.02 x 2 = 16

So she will be paid $16 in the first two years.

3 0
3 years ago
Read 2 more answers
Solve the system -10=-2y+x 6y=3x+11
belka [17]

Answer: No Solutions exist

Step-by-step explanation:

We have the following system of equations

-10=-2y+x

6y=3x+11

Rewriting the second equation we have:

-11=-6y+3x

Now we multiply the first equation by -3 and add it to the second equation

30=6y-3x

-11=-6y+3x

---------------------------------

19=0

Equality is not satisfied. Then the system has no solution

5 0
3 years ago
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