You change the independent variable in an experiment
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Answer:</h3>
1026.05 kJ
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Explanation:</h3>
- The Quantity of heat is calculated by multiplying the mass of a substance by specific heat capacity and the change in temperature.
- However, condensation takes place at a constant temperature.
- Therefore, Quantity of heat is calculated by multiplying mass by the latent heat of vaporization.
In this case we are given;
Mass of steam as 454 g
To calculate the amount of heat released we must know the value of latent heat of vaporization;
The latent heat of vaporization of steam is 2260 J/g
Therefore;
Heat released, Q = 454 g × 2260 J/g
=1026040 Joules
But, 1000 joules = 1 kilo-joules
Thus, Q = 1026.04 kJ
Hence, the amount of heat released is 1026.05 kJ
When Ag₂S dissolves, it dissociates as follows;
Ag₂S ---> 2Ag⁺ + S²⁻
First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.
If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.
ksp gives the solubility constant
ksp = [Ag⁺]²[S²⁻]
ksp = [2y]²[y]
4y³ = 8.00 x 10⁻⁵¹
y³ = 2 x 10⁻⁵¹
y = 1.26 x 10⁻¹⁷ mol/L
molar mass = 247.8 g/mol
solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L
Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L
