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vazorg [7]
3 years ago
10

A square sheet of art paper has an area of 625 square inches. What is the minimum side length of an easel that supports the whol

e sheet of paper?
Mathematics
2 answers:
Mila [183]3 years ago
7 0
If the area of the paper is 625 sq in, the length of one side of this square is sqrt(625 sq in), or 25 inches.  That's the min. side length of an easel that is to support the whole sheet of paper along its lowest side.
svetlana [45]3 years ago
4 0

area of a square = side^2

 to find the length of a side using area find the square root of the area

sqrt(625) = 25

so the easel has to be at least 25 inches

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The inequality can be:
150x \leqslant 3000
Now you divide both sides by 150 to get the #of boxes.

3000 \div 150
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Draw Y=3x-2 on a grid
Afina-wow [57]
Just subsitute values for x and get values for y
(x,y)
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8 0
3 years ago
The area of a rectangle is 56 cm. the length is 2 less than x and the width is 5 less than twice of x. solve for x
Nostrana [21]

Answer:

x=\frac{9+\sqrt{449}}{4}

Step-by-step explanation:

The area of a rectangle is:

A=l\cdot w

First let's write both the length and the width in terms of x:

l=x-2

<u>How we obtained the answer</u>:

The question states the length is "2 less than x". In this case, "less" is a keyword that represents subtraction. Therefore, "2 less than x" is "x-2".

w=2x-5

<u>How we obtained the answer</u>:

The question states the width is "5 less than twice of x". First, start by figuring out what "twice of x" is. The keyword is "twice" which represents multiplication. Therefore, "twice of x" can be written as "2x". Then, using the same keyword from before ("less"), "5 less than..." represents "2x-5".

Given:

Area = 56 cm

l=x-2

w=2x-5

Find:

x

A=l\cdot w

56=(x-2)(2x-5)

FOIL (Firsts, outsides, insides, lasts):

56=2x^2-4x-5x+10\\56=2x^2-9x+10

Subtract 10 from both sides:

46=2x^2-9x

Subtract 46 from both sides (forms a quadratic equation):

0=2x^2-9x-46

Use the quadratic formula:

{x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}  where 0=ax^2+bx+c

Therefore:

x=\frac{9\pm\sqrt{81-4(2)(-46)}}{2(2)}\\x=\frac{9\pm\sqrt{81+368}}{4}\\\\x=\frac{9\pm\sqrt{449}}{4}

The answer is:

x=\frac{9+\sqrt{449}}{4}

This is because if we used subtraction, we would get a negative value, and we cannot have a negative length/width.

4 0
2 years ago
Calvin types 4 pages in 1/5 hour. The average page contains 250 words. What is Calvin's approximate typing speed in words per mi
RoseWind [281]

Answer:

83 1/3 words per minute

or approximately 83 words per minute

Step-by-step explanation:

4 pages * 250 words/ page = 1000 words

1/5 hour * 60 minutes/ 1 hour = 12 minutes

1000 words / 12 minutes = 83.333333333.... words per minute

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7 0
3 years ago
What is 6,242 ÷ 4 help me please i really dont get it
coldgirl [10]
6242 divided by 4 equals 1,560.5
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