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vazorg [7]
3 years ago
10

A square sheet of art paper has an area of 625 square inches. What is the minimum side length of an easel that supports the whol

e sheet of paper?
Mathematics
2 answers:
Mila [183]3 years ago
7 0
If the area of the paper is 625 sq in, the length of one side of this square is sqrt(625 sq in), or 25 inches.  That's the min. side length of an easel that is to support the whole sheet of paper along its lowest side.
svetlana [45]3 years ago
4 0

area of a square = side^2

 to find the length of a side using area find the square root of the area

sqrt(625) = 25

so the easel has to be at least 25 inches

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You need 48 packages for each employee to have 3 uniforms

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3 years ago
The amount of money Kelly earns is proportional to the number of hours she works. Kelly earns $32.40 working 4 hours. Create an
UkoKoshka [18]
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4 0
3 years ago
Jan spends part of her year as a member of a gym. She then finds a better deal at another gym, so she cancels her membership wit
ivann1987 [24]

Answer:

Number of months spent in first gym = 9

Number of months spent in second gym = 3

Step-by-step explanation:

Let she spent x months in a year at first gym and y months in a year at second gym

Now, there are 12 months in one year

⇒ x + y = 12

y = 12 - x .......(1)

Now, total money she spent in one year = $825

⇒ 75·x + 50·y = 825 .........(2)

Putting value of y from equation (1) in equation (2)

75·x + 50·(12 - x) = 825

⇒ 75·x - 50·x + 600 = 825

⇒ 25·x = 225

⇒ x = 9

Now, putting this value of x in equation(1)

⇒ y = 12 - 9

⇒ y = 3

Hence, number of months spent in first gym = 9

And number of months spent in second gym = 3

7 0
4 years ago
If f(x) = 5x − 3, which expression represents its inverse function?
Drupady [299]

Answer:

B.

\frac{x+3}{5}

Step-by-step explanation:

5x - 3 = y then 5x = y + 3 then  x = (y + 3)/5

then the inverse function of f is : (x+3)/5

6 0
3 years ago
Can someone help me write an equation for this problem?
11Alexandr11 [23.1K]
Y=800+175(9)
And then just solve for y.
8 0
3 years ago
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