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krok68 [10]
3 years ago
12

I need the answer for this question I’m stuck

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

i(-5i + 6) + 8(3 + 7i)

= -5i^2 + 6i + 24 + 56i

= 5 + 24 + 62i (because -i^2 = 1)

= 29 + 62i

Answer is C.

You might be interested in
If f(x) = 2x + 3 for all values of x, what is the value of f(-3)?​
IrinaK [193]

Answer:

f(-3)= -3

Step-by-step explanation:

We are given the function:

f(x) = 2x+3

and asked to find f(-3). Essentially, we want to find f(x) when x is equal to -3.

Therefore, we can substitute -3 for each x in the function.

f(x)= 2x+3 at x= -3

f(-3)= 2(-3) +3

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction

Multiply 2 and -3.

f(-3) = (2*-3) +3

f(-3)= (-6)+3

Add -6 and 3.

f(-3)= (-6+3)

f(-3)= -3

If f(x)= 2x+3, then<em> f(-3)= -3</em>

7 0
3 years ago
Add.<br> (4x2 - 2x) + (5x-7)
Sloan [31]

Answer:

4x²+3x-7 is the answer

Step-by-step explanation:

=(4x²-2x)+(5x-7)

opening brackets

=4x²-2x+5x-7

=4x²+3x-7

i hope this will help you :)

7 0
4 years ago
How many lines of symmetry does the following figure have? <br><br>1<br><br>3<br><br>4<br><br>5​
iren2701 [21]

Answer:

1

Step-by-step explanation:

It has 1 lines of symmetry

Hopes this helps

#ViolentJax

6 0
2 years ago
In APQR, p = 690 cm, a = 290 cm and r=450 cm. Find the measure of ZQ to the
katen-ka-za [31]

9514 1404 393

Answer:

  16.8°

Step-by-step explanation:

The Law of Cosines can be rearranged to give the angle measure.

  angle Q = arccos((p² +r² -q²)/(2pr))

  angle Q = arccos((690² +450² -290²)/(2×690×450))

  angle Q = arccos(594500/621000) ≈ 16.7985°

The measure of angle Q is about 16.8°.

3 0
3 years ago
Question 1
vivado [14]

Answer:

For Lin's answer

Step-by-step explanation:

When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.

Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.

Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.

7 0
3 years ago
Read 2 more answers
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