Answer:
2002
Step-by-step explanation:
Given :
To Find : Determine the year in which the country had or will have a population of 189,698,000.
Solution:
We are given an equation which represents The population of a certain country.

where P is the population in millions.
x is the number of years since 1980
Now we are supposed to find the year in which the country had or will have a population of 189,698,000.
P represents population in millions. Then, P
=
189.698
Substitute P in equation :





So, x≈ 22
Since x is the number of years since 1980
So, the year in which the country had or will have a population of 189,698,000. = 1980+22 = 2002
Hence the country had or will have a population of 189,698,000 in 2002.